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Andre45 [30]
3 years ago
5

Calculate the mass defect for the isotope thorium-234

Chemistry
2 answers:
kiruha [24]3 years ago
8 0

Answer:1.85864 amu

Explanation:

Just got this problem

inn [45]3 years ago
6 0
Mass defect is defined as the difference or discrepancy between the mass of the nucleons and the mass of the nucleus. the nucleons involved are the protons and neutrons. 
mp  = 1.6727 x 10-24 g = <span>1.007316 amu</span>mn = 1.6750 x 10-24 g = <span>1.008701 amu</span>
mTh 234 = 234 g/mol = 234 amu

Th234 (protons = 90; neutrons = 144)
mass defect = mp*90 + mn *144 - 234
mass defect = 1.911384 amu

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Argon, which comprises almost 1 percent of the atmosphere, is approximately 27 times more abundant than CO2 but does not contrib
kykrilka [37]

B. Argon's vibrational energy is not excited by infrared radiation.

Explanation:

The property of carbon dioxide to get excited by infrared electromagnetic radiation is what qualifies it as a greenhouse gas. When infrared from the earth's surface is reflecting back to space, some of the radiation is absorbed and remitted by the carbon-dioxide molecules in the atmosphere. This causes a phenomenon called greenhouse effect that causes the atmosphere to be relatively warmer. The more the carbon dioxide molecules the more the greenhouse effect.

6 0
3 years ago
What type of a reaction takes place when atoms or molecules rearrange to form new substances
GREYUIT [131]
A chemical reaction happens when the atoms or molecules rearrange to form a new substance


6 0
3 years ago
Read 2 more answers
An atom of argon has a radius rar = 88 pm and an average speed in the gas phase at 25°C of 172 m/s.
Rudik [331]

Answer:

1.2* 10³ rNe.

Explanation:

Given speed of neon=350 m/s

Un-certainity in speed= (0.01/100) *350 =0.035 m/s

As per heisenberg uncertainity principle

Δx*mΔv ≥\frac{h}{4\pi }

4π

h

..................(1)

mass of neon atom =\frac{20*10^{-3} }{6.22*10^{-23} } =3.35*10^{-26} kg

6.22∗10

−23

20∗10

−3

=3.35∗10

−26

kg

substituating the values in eq. (1)

Δx =4.49*10^{-8}10

−8

m

In terms of rNe i.e 38 pm= 38*10^{-12}10

−12

Δx=\frac{4.49*10^{-8} }{38*10^{-12} }

38∗10

−12

4.49∗10

−8

=0.118*10^{4}10

4

* (rNe)

=1.18*10³ rN

= 1.2* 10³ rNe.

Explanation:

This is the answer

7 0
3 years ago
How many grams of iron oxide, Fe2O3 will be produced if 165 g of O2 gas is supplied? (follow the same steps as mol to mol, only
forsale [732]

Answer:

m_{Fe_2O_3}=549gFe_2O_3

Explanation:

Hello there!

In this case, according to the given chemical reaction for this problem about stoichiometry:

4Fe+3O_2\rightarrow 2Fe_2O_3

Whereas there is a 3:2 mole ratio of oxygen (molar mass = 32.0 g/mol) to iron (III) oxide (molar mass = 159.69 g/mol) and therefore, the correct stoichiometric setup is:

m_{Fe_2O_3}=165gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molFe_2O_3}{3molO_2} *\frac{159.69gFe_2O_3}{1molFe_2O_3}  \\\\m_{Fe_2O_3}=549gFe_2O_3

Regards!

8 0
3 years ago
How many valence electrons does rubidiumn have?
vlada-n [284]

Answer:

1

Explanation:

I believe it really only has 1 valence electrons

7 0
3 years ago
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