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Alexxx [7]
2 years ago
7

Solve for h. A=3h Can anyone help me?

Mathematics
1 answer:
IgorC [24]2 years ago
8 0

Answer:

h = 3/A

Step-by-step explanation:

A = 3h

Divide both sides by 3 to isolate h:

A/3 = 3h/3

Simplify and get

A/3 = h or h = A/3

Hope this helps!

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If the altitude is √7, find the volume. 36√7 cu. units 18√7 cu. units 12√7 cu. units
rosijanka [135]

Answer:

Volume = 12\sqrt{7} cubic units

Step-by-step explanation:

Volume of the square pyramid is given as ⅓*area of base*height of pyramid.

Where,

Area of base = 6*6 = 36

Height of pyramid = altitude = \sqrt{7} units

Plug the values into the formula to find volume.

Volume = \frac{1}{3}*36*\sqrt{7}

Volume = 12*\sqrt{7}

Volume = 12\sqrt{7} cubic units

8 0
3 years ago
Tell me some irrational numbers​
lana [24]

Answer:

square root of 2, pi, square root of 5, square root of 10, square root of 3, square root of 15

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%2018%20%5E%20%7B%20n%20%2B%201%20%7D%20%5Ctimes%203%20%5E%20%7B%201%20-%20n%20%7
Rufina [12.5K]

Answer:

4 \times  {3}^{n + 3}

Step-by-step explanation:

\frac{ {18}^{n + 1}  \times {3}^{1 - n}}{  {2}^{n - 1}  }

\frac{ {3}^{2n + 2}  \times  {2}^{n + 1}  \times  {3}^{1 - n} }{ {2}^{n - 1} }

{3}^{2n + 2}  \times  {2}^{2}  \times  {3}^{1 - n}

{3}^{2n + 2}  \times 4 \times  {3}^{1 - n}

= 4 \times  {3}^{n + 3}

8 0
3 years ago
Read 2 more answers
Let f(x)= 7-2x Find a. f(4) b. f(h) c. f(4) + f(h) d. f(3+h)
anyanavicka [17]

Step-by-step explanation:

a) f(4) = 7-2(4)

= -1

b) f(h) = 7-2(h)

= 7-2h

c) f(4) + f(h) = -1 +(7-2h)

= 6-2h

h = 3

d) f(3+h) = 7-2(3+h)

= 7-6-2h

= -1-2h

2h= -1

h = -1/2

p/s = if the real answer is different with my answer, tell me also please. Im just a student that still learning.

4 0
3 years ago
3. Brenda's school is selling tickets to a spring musical. On the first day of
Natalija [7]

Answer:

The Answer is that Senior Citizen Tickets cost: $4 and Child tickets cost: $7.

Step-by-step explanation:

Let s = the cost of senior citizen tickets

Let c = the cost of child tickets

The number of tickets sold for each type added together equals the sales for each day. Equations below:

Day 1

3s + 9c = $75

Solve for s:

3s = 75 - 9c

s = 25 - 3c

Day 2

8s + 5c = $67

By substitution:

8(25 - 3c) + 5c = 67

200 - 24c + 5c = 67

-19c = -133

c = -133 / -19 = $7 cost for child tickets.

Solve for s:

s = 25 - 3c

s = 25 - 3(7)

s = 25 - 21 = $4 cost for senior citizen tickets.

Proofs:

Day 1

3s + 9c = $75

3(4) + 9(7) = 75

12 + 63 = 75

75 = 75

Day 2

8s + 5c = $67

8(4) + 5(7) = 67

32 + 35 = 67

67 = 67

4 0
3 years ago
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