All categories

2 years ago

Solve for h. A=3h Can anyone help me?

Mathematics

1 answer:

IgorC [24]2 years ago

8 0

Answer:

h = 3/A

Step-by-step explanation:

A = 3h

Divide both sides by 3 to isolate h:

A/3 = 3h/3

Simplify and get

A/3 = h or h = A/3

Hope this helps!

You might be interested in

Please help me please

Jlenok [28]

None of them because they are not in order

5 0

3 years ago

Identify the following as either an expression, an equation, or neither.<br>3x+(10 - x) = 3

n200080 [17]

The following is an expression.

6 0

3 years ago

Help Please. im giving 20 points

UNO [17]

Answer:the other leg is 6

Step-by-step explanation:

13-5=6 so math dosent lie so if I’m not mistaken your answer would be 5!!! Have a good day, hope it helps!

4 0

3 years ago

Read 2 more answers

Somebody please help me!!!

goldfiish [28.3K]

Answer:

Step-by-step explanation:

(2,4)

7 0

3 years ago

Read 2 more answers

Pre-calc questions (trignometry)

miv72 [106K]

Answer: (1a) 250° (1b) 70° (2) see below

<u>Step-by-step explanation:</u>

1a) -110 + 360 (one rotation clockwise) = 250°

1b) 430 - 360 (one rotation counterclockwise) = 70°

2) sec Ф = -8/5 in Quadrant III

Quadrant III identifies that both sin (y) and cos (x) are negative.

sec = r/x --> r = 8, x = -5, and y = -√39

(Use Pythagorean Theorem x² + y² = r² to solve for y)

$\sin\theta=\dfrac{y}{r}=\dfrac{-\sqrt{39}}{8}$ $\csc\theta=\dfrac{r}{y}=\dfrac{-8}{\sqrt{39}}$ rationalized = $\dfrac{-8\sqrt{39}}{39}$

$\cos\theta=\dfrac{x}{r}=\dfrac{-5}{8}$ $\sec\theta=\dfrac{r}{x}=\dfrac{-8}{5}$ (GIVEN)

$\tan\theta=\dfrac{y}{x}=\dfrac{\sqrt{39}}{5}$ $\cot\theta=\dfrac{x}{y}=\dfrac{-5}{-\sqrt{39}}$ rationalized = $=\dfrac{5\sqrt{39}}{39}$

NOTE THAT YOU ARE ALLOWED A MAXIMUM OF 3 QUESTIONS PER POST. Please repost #3 and #4 as a different question and I will answer them.

8 0

3 years ago