How many molecules are in 3.50 moles of NO2

The method of changing one or more chemical compounds

horsena [70]

Answer:

chemical process

Explanation:

4 0

3 years ago

Your body uses about 24 grams of glucose to run cellular respiration. How many molecules does your body need for cellular respir

stealth61 [152]

10000000000303033830330291

3 0

2 years ago

A stock bottle of an acid reads: 56% by mass and 1.25 specific gravity. If the molar mass of the acid is 70g, find the mole per

TiliK225 [7]

Answer:

10 mol / dm³

Explanation:

Cubic decimeter is the same unit as liter; so, mole per cubic decimeter is mole per liter, and that is the unit of concentration of molarity. Thus, what is asked is the molarity of the solution. This is how you find it.

1. Take a basis: 1 dm³ = 1 liter = 1,000 ml

2. Calculate the mass of 1 liter (1,000 ml) of solution:

density = mass / volume ⇒ mass = density × volume

Here, the density is given through the specific gravity

Scpecific gravity = density of acid / density of water

Take density of water as 1.00 g/ml.

density of solution = 1.25 g/ml

mass solution = 1.25 g/ml × 1,000 ml = 1,250 g

3. Calculate the mass of solute (pure acid)

% m/m = (mass of solute / mass of solution) × 100

56 = mass of solute / 1,250 g × 100

mass of solute = 56 × 1,250g / 100 = 700 g

4. Calculate the number of moles of solute:

moles = mass in grams / molar mass = 700 g / 70 g/mol = 10 mol

5. Calculate molarity (mol / dm³)

M = number of moles of solute / liter of solution = 10 mol / 1 liter = 10 mol/liter.

5 0

3 years ago

What is the balanced equation if copper metal reacts with oxygen gas to form copper oxide

katrin [286]

Answer:

2Cu + O2 ----------------> 2CuO

5 0

3 years ago

If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3

ss7ja [257]

Answer:- 27.7 grams of $PbI_2$ are produced.

Solution:- The balanced equation is:

$Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3$

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of $Pb(NO_3)_2 = 207.2+2(14.01)+6(16) = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2$ = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

$28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})$

= $39.0gPbI_2$

$18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})$

= $27.7gPbI_2$

From above calculations, NaI gives least amount of $PbI_2$ , so the answer is, 27.7 g of $PbI_2$ are produced.

8 0

2 years ago