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3 years ago

What is the molar ratio of Li to N2 in the given reaction? 6Li+N2 —> 2Li3N

1 answer:

4 0

The molar ratio of Li to N2 in the equation 6Li + N2 —> 2Li3N is:

6 moles Li / 1 mole N2

This is because this equation is balanced, and therefore the mole ratios exist just as they do in the reactants of the equation (there are 6 parts Li per each part N2 in order to create the product; this also holds true for moles).

Hope this helps!

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A 50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If a car's cooli

Diano4ka-milaya [45]

Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

50/50 ethylene glycol (EG):water

V = 4.70 gal

ρ(EG) = 1.11 g/mL

ρ(water) = 0.988 g/mL

Calculations:

The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.

1. Moles of EG

$\rm n = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{1000 mL}}{\text{1 L}} \times \dfrac{\text{1.11 g}}{\text{1 mL}} \times \dfrac{\text{1 mol}}{\text{62.07 g}} = \text{159 mol}$

2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

5. Boiling point

$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

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3 years ago

How many grams of calcium phosphate can be produced when 78.5 grams of calcium hydroxide reacts with excess phosphoric acid? Unb

sasho [114]

Once you balance the enquation you "switch partners" of the element (negative charge to positive charge)

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2 years ago

What happens when two hydrogen atoms enter the ETS as part of either NADH or FADH2?

murzikaleks [220]

I'm pretty sure its D

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2 years ago

Read 2 more answers

19.

solmaris [256]

Answer:

В. No, because the mass of the reactants is less than the mass of the products.

Explanation:

Chemical equation:

NaBr + Cl₂ → 2NaCl + Br₂

The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.

There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.

Balanced chemical equation:

2NaBr + Cl₂ → 2NaCl + Br₂

Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.

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2 years ago

How is a compound different from a mixture? *

andreyandreev [35.5K]

Answer:

a. mixtures are created through physical changes and compounds are created through chemical reactions

Explanation:

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2 years ago