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riadik2000 [5.3K]
3 years ago
9

Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho

ws Marcus’s measured and calculated values. Substance Mass (g) Volume (cm3) Density (g/cm3) aluminum 5.7 2.1 2.7 copper 14.4 1.6 9.0 iron 9.5 1.2 7.9 titanium 8.6 1.8 4.8 Next, Marcus obtained another sample, which is made of one of the four substances that he had already measured. The table shows Marcus’s measured values for this unknown sample. Substance Mass (g) Volume (cm3) ? 9.5 2.1 What is the unknown sample made of?
Chemistry
2 answers:
gayaneshka [121]3 years ago
5 0

the answer is D) Titanium. you divide the mass by volume and titanium has the closest density yo the number you get. I also chose titanium and got it right. goodluck


larisa [96]3 years ago
4 0

Answer:

The unknown substance is made up titanium.

Explanation:

Density is defined as mass present in the unit volume of the substance.It is an intensive property.

Density of Aluminium = 2.7 g/cm^3

Density of copper = 9.0 g/cm^3

Density of iron = 7.9 g/cm^3

Density of titanium = 4.8 g/cm^3

Density of the unknown substance:

\frac{mass}{Volume}=\frac{9.5 g}{2.1 cm^3}=4.5 g/cm^3

The density of the unknown substance is close to the density of the titanium. This means that unknown substance is made of titanium.

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Describe the famous experiment related to gravity that Galileo may have performed. Include the results. Also, state whether the
vivado [14]

Answer:

Galileo performed a famous experiment where he used a ball rolling on a ramp (inclined plane) to study the motion of objects under the influence of gravity. The ramp allowed him to make more precise measurements because the ball moved more slowly along the ramp than if it were simply dropped. Galileo discovered through this experiment that the objects fell with the same acceleration, proving his prediction true, while at the same time disproving Aristotle's theory of gravity (which states that objects fall at speed proportional to their mass). Galileo's conclusion from this thought experiment was that no force is needed to keep an object moving with constant velocity. Newton took this as his first law of motion. One result of the experiment surprised Galileo, and one surprises us. Galileo found that the heavy ball hit the ground first, but only by a little bit. Except for a small difference caused by air resistance, both balls reached nearly the same speed. And that surprised him. According to history, Galileo’s experiment on falling bodies largely contributed to Isaac Newton’s Law of Gravity. In Galileo’s experiment, he is said to have dropped balls from the Leaning Tower of Pisa. The balls were made of the same material but had different masses. Galileo set out to prove that the time it took for these objects to reach the ground would be the same. Galileo proved that objects reached the ground at the same time,

Explanation:

I think this is right & I hope this helped

4 0
3 years ago
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dlinn [17]
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4 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
Electrolysis can be used for all of the following, except A. separating metals from ores. B. plating objects with metal coatings
NemiM [27]

The answer is D. recharging batteries.

6 0
3 years ago
How many liters of 0.615 M NaOH will be needed to raise the pH of 0.385 L of 5.13 M sulfurous acid (H2SO3) to a pH of 6.247?
givi [52]

Answer:

Volume of NaOH required = 3.61 L

Explanation:

H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:

H2SO3\leftrightarrow H^{+}+HSO3^{-} --------(1)

where,  Ka1 = 1.5 x 10–2  or pKa1 = 1.824

HSO3^{-}\leftrightarrow H^{+}+SO3^{2-} --------(2)

where,  Ka2 = 1.0 x 10–7 or pKa2 = 7.000

The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.

Step 1:

Based on equation(1), at the first eq point:

moles of H2SO3 = moles of NaOH

i.e. \ 5.13\  moles/L*0.385L = moles\  NaOH\\therefore, \ moles\  NaOH = 1.98\ moles\\V(NaOH)\ required = \frac{1.98\ moles}{0.615\ moles/L} =3.22L

Step 2:

For the second equivalence point setup an ICE table:

                  HSO3^{-}+OH^{-}\leftrightarrow H2O+SO3^{2-}

Initial           1.98                    ?                                       0

Change      -x                       -x                                       x

Equil           1.98-x                 ?-x                                    x

Here, ?-x =0 i.e. amount of OH- = x

Based on the Henderson buffer equation:

pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles

Volume of NaOH required is:

\frac{0.634\ moles}{0.615 moles/L}=0.389L

Step 3:

Total volume of NaOH required = 3.22+0.389 =3.61 L

3 0
3 years ago
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