Answer:
21.8
Explanation:
add both because there both forces are going down
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
<h3>What is IUPAC convention?</h3>
IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).
Types of IUPAC Nomenclature of a few important aliphatic compounds:
- Alkane
- Alkene
- Alkyne
Example :
Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆
Formation of alkyl group:
Methane (CH₄) Remove 1 hydrogen (H) convert to methyl (H₃-C-)
Example: Propyl (-CH₃ - CH₂ - CH₂ - )
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
Learn more about IUPAC convention, Here:
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Answer;
12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.
Explanation:
Using a balanced chemical equation we can identify the number of carbon, hydrogen, and oxygen atoms in sugar.
CxHyOn + 12O₂ → 11 H₂O + 12CO₂
When an equation is completely balanced, then the number of each atom of an element is equal on the reactant side and the product side.
Therefore;
For carbon; x = 12
For Hydrogen; y = (11×2) = 22
For Oxygen; n + (12×2) = 11 + (12×2)
= n + 24 = 11 + 24
n = 11
Therefore the sugar has, 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.
Thus the balanced equation would be;
C₁₂H₂₂O₁₁ + 12O₂ → 11 H₂O + 12CO₂
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hope this helps
