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3 years ago

11

Exothermic reactions have _____ net bond energy.

2 answers:

Elena L [17]3 years ago

6 0

I think it has a negative reaction.

nika2105 [10]3 years ago

4 0

Negative yeahhbb is the answer

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The student adds 0.0010 mol of NaOH(s) to solution Y, and adds 0.0010 mol of NaOH(s) to solution Z. Assume that the volume of ea

julia-pushkina [17]

Answer:

The answer is in the explanation.

Explanation:

A buffer is defined as the aqueous mixture of a weak acid and its conjugate base or vice versa. Buffers are able to avoid the pH change of a solution when strong acid or bases are added (As NaOH).

Based on the experiment, it is possible that the solution Z was a buffer and Y another kind of solution. For this reson, pH of the solution Y changes much more than the pH of solution Z changes despite the amount of NaOH added is the same in both solutions.

6 0

3 years ago

How many molecules of ethane ( C2H6) are present in 0.197g of C2H6?

Brut [27]

Answer:

3.945 x 10²¹ molecules

Explanation:

Firstly, we need to calculate the no. of moles using the relation:

n = mass/molar mass = (0.197 g)/(30.07 g/mol) = 6.55 x 10⁻³ mol.

It is known that every 1.0 mol of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).

<em>∴ 0.197 g of C₂H₆ will contain</em> = (6.55 x 10⁻³ mol)(6.022 x 10²³) = <em>3.945 x 10²¹ molecules.</em>

4 0

3 years ago

Read 2 more answers

Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which

Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride = 0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be: $= \dfrac{5 \ kg }{1590 \ kg/m^3}$

= 0.0031 m³

Suppose $\beta$ is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

$\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT$

$In ( \dfrac{V_2}{V_1}) = \beta (T_2-T_1)$

$V_2 = V_1 \times exp (\beta (T_2-T_1))$

$V_2 = 0.0031 \ m^3 \times exp (1.2 \times 10^{-3} \times 20)$

$V_2 = 0.003175 \ m^3$

However; the workdone = -PdV

$W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)$

W = - 7.6 J

The heat energy Q = Δ h

$Q = mC_p(T_2-T_1)$

$Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20$

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0

3 years ago

A matter with very far apart molecules

Ierofanga [76]

Answer:

The molecules in a gas are very far apart so they can be squeezed together into a smaller space.

4 0

3 years ago

Organisms that get energy by eating dead organisms are called *

Licemer1 [7]

Answer:

The Answer is A. Scavengers

7 0

3 years ago