Answer:
hello your question is incomplete attached below is the complete question
<em>answer</em> :
To ( inside temperature ) = 598 K
TL ( outside temperature ) = 594 k
Explanation:
a) Determine the surface temperature To and TL based on the known conditions provided in the drawing
To ( inside temperature ) = 598 K
TL ( outside temperature ) = 594 k
attached below is the detailed solution
Answer:
7 m to the left of the line of fire.
213.55 m from the foot of the wall.
7.25 m above the ground.
Explanation:
Let's assume the height is the y-direction, the line of fire is in x-direction. Since there is no external force acting in z-direction, z-coordinate of the center of mass of he ball should be zero. In order to make z-coordinate zero other ball should fall symmetrically with respect to z-axis. So, z-coordinate of 19 kg ball = -7 m.
Hence, 7 m to the left of the line of fire.
The balls do not have any external force in x-direction. Thus, in x-direction, the center of mass should move with constant velocity. x-coordinate of center of mass at t = 1.5 s is:
Hence, 213.55 m from the foot of the wall.
Height fallen by the center of mass at t = 1.5 s.
Hence, y-coordinate of the center of mass is:
Hence, 7.25 m above the ground.
Answer:
33.429 N-m
Explanation:
Given :
Inclination angle of two shaft, α = 20°
Speed of shaft A, = 1000 rpm
Mass of flywheel, m = 30 kg
Radius of Gyration, k =100 mm
= 0.1 m
Now we know that for maximum velocity,
= 1064.1 rpm
Now we know
Mass of flywheel, m = 30 kg
Radius of Gyration, k =100 mm
= 0.1 m
Therefore moment of inertia of flywheel, I = m.
=30 X
= 0.3 kg-
Now torque on the output shaft
T₂ = I x ω
= 0.3 X 1064.2 rpm
=
= 33.429 N-m
Torque on the Shaft B is 33.429 N-m