Answer:
>>pounds=13.2
>>kilos=pounds/2.2
Explanation:
Using Matlab to write the program, consider at any time when the weight in pounds is 13.2 lb, this variable of weight is created in MATLAB by typing >>pounds=13.2. To convert it from lb to Kg, we simply divide it by 2.2 hence the second command to created is kilos. For this, the output of the program will be 6 Kg.
Answer
No;
The two flows are not dynamically similar
Explanation: Given
T∞,1 = 800k
V∞,1 = 200m/s
p∞,1 = 1.739kg/m³
T∞,2 = 200k
V∞,2 = 100m/s
p∞,2 = 1.23kg/m³
Size1 = 2 * Size2 (L1 = 2L2) Assumptions Made
α ∝√T
μ∝√T Two (2) conditions must be met if the two flows are to be considered similar.
Condition 1: Similar Parameters must be the same for both flows
Condition 2: The bodies and boundaries must be genetically true. Condition 2 is true
Checking for the first condition...
Well need to calculate Reynold's Number for both flows
And Check if they have the same Reynold's Number Using the following formula
Re = pVl/μ
Re1 = p1V1l1/μ1 Re2 = p2V2l2/μ2 Re1/Re2 = p1V1l1/μ1 ÷ p2V2l2/μ2
Re1/Re2 = p1V1l1/μ1 * μ2/p2V2l2
Re1/Re2 = p1V1l1μ2/p2V2l2μ1
Re1/Re2 = p1V1l1√T2 / p1V1l1√T1
Re1/Re2 = (1.739 * 200 * 2L2 * √200) / (1.23 * 100 * L2 * √800)
Re1/Re2 = 9837.2/3479
Re1/Re2 = 2,828/1
Re1:Re2 = 2.828:1
Re1 ≠ Re2,
So condition 1 is not satisfied Since one of tbe conditions is not true, the two flows are not dynamically similar
Answer:
Velocity of rock fall collision, v = 13.21 m/sec
Explanation:
Detailed explanation given in the attached document.