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scoray [572]
3 years ago
9

Looookkk at diiiiiiiisssss

Engineering
2 answers:
kipiarov [429]3 years ago
7 0

Answer:

Omggggggghgggggg...

ioda3 years ago
5 0

Answer:

Dude that's so cool.

Explanation:

It's pretty cool, you should mark me brainliest

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8. Air at 25C, 100 kPa and air at 50C, 200 kPa at 1 to 1 volume ratio are mixed inside an adiabatic compressor to 55C, 500 kPa a
quester [9]

Answer:

Workdone, w = 68.935 kJ

Explanation:

m1h1 + m2h2 + Q = m3h3 - Wc

Final mass of mixture,

m3 = m1 + m2 = 5kg

p1V1 = m1R1T1

p2V2 = m2R2T2

Since they are at 1:1,

V1 = V2 and R1 = R2

Comparing equations,

p1/p2 = (m1/m2) x (T1/T2)

m1/m2 = (100/200) x ((50 + 273)/(25+273))

m1/m2 = 0.542

m1 = 0.542m2

m3 = m1 + m2

5 = m2 + 0.542m2

m2 = 3.243kg

m1 = 1.757 kg

Workdone is given as,

Wc = m3h3 - m1h1 - m2h2

h = Cp x T, since air is an ideal gas

Cp = 1.005kJ/kGK

Wc = (5 x 1.005 x (55+273)) - (1.757 x 1.005 x 298) -(3.243 x 1.005 x 323)

Wc = 68.935 kJ

8 0
4 years ago
What are examples of Energy careers? Check all that apply. Carpenter Video Editor Electrical Power-Line Installer Printing Press
Rasek [7]

Answer:

C,E,F

Explanation:

Right on edge 2021

7 0
3 years ago
Read 2 more answers
Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC . Part A What is the electric field
Alchen [17]

Answer:

A. E = 1.512\times 10^{5}\ V

B. 151.2 V

C. E = 1.512\times 10^{5}\ V

D. V = 302.4 V

Solution:

As per the question:

Area of the plates of the parallel plate capacitors, A = 2.30\times 2.30 = 5.29\ cm^{2} = 5.29\times 10^{- 4}\ m^{2}

Charge on the plates of the capacitor, Q_{c} = \pm 0.708\ nC = \pm 0.708\times 10^{- 9} \C

Now,

(A) To calculate the electric field strength, E when the separation distance, d = 1.00 mm = 10^{- 3}\ m:

E = \frac{Q}{\epsilon_{o}A}

E = \frac{0.708\times 10^{- 9}}{8.85\times 10^{- 12}\times 5.29\times 10^{- 4}} = 1.512\times 10^{5}\ N/C

(B) To calculate potential difference between the plates:

V = Ed = 1.512\times 10^{5}\times 10^{- 3} = 151.2V

(C) Electric field strength when spacing is 2 mm, i.e., 2\times 10^{- 3}\ m:

E = \frac{Q}{\epsilon_{o}A}

Since, the above expression of the electric field shows that it does not depend on the separation distance between the plates thus it will remain same, i.e., 1.512\times 10^{5}\ V

(D) Potential difference across the capacitor when d = 2\times 10^{- 3}\ m:

V = Ed = 1.512\times 10^{5}\times 2\times 10^{- 3} =302.4\ V

7 0
4 years ago
Elijah wants to make some changes to a game that he is creating. Elijah wants to move the bleachers to the right, the coaches to
Ahat [919]

Answer:

the editor

Explanation:

the variable is usually a number, and the conditional loop has nothign to do with movement/ where something is located

7 0
3 years ago
Read 2 more answers
Given : f(x) = x³- 7x²+ 36 Draw the graph of f neatly on F graph paper. Clearly indicate an Intercepts and coordinates of turnin
vichka [17]

Answer:

Explanation:

xx=33 vvalues

7 0
3 years ago
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