Answer:
Workdone, w = 68.935 kJ
Explanation:
m1h1 + m2h2 + Q = m3h3 - Wc
Final mass of mixture,
m3 = m1 + m2 = 5kg
p1V1 = m1R1T1
p2V2 = m2R2T2
Since they are at 1:1,
V1 = V2 and R1 = R2
Comparing equations,
p1/p2 = (m1/m2) x (T1/T2)
m1/m2 = (100/200) x ((50 + 273)/(25+273))
m1/m2 = 0.542
m1 = 0.542m2
m3 = m1 + m2
5 = m2 + 0.542m2
m2 = 3.243kg
m1 = 1.757 kg
Workdone is given as,
Wc = m3h3 - m1h1 - m2h2
h = Cp x T, since air is an ideal gas
Cp = 1.005kJ/kGK
Wc = (5 x 1.005 x (55+273)) - (1.757 x 1.005 x 298) -(3.243 x 1.005 x 323)
Wc = 68.935 kJ
Answer:
A. 
B. 151.2 V
C. 
D. V = 302.4 V
Solution:
As per the question:
Area of the plates of the parallel plate capacitors, A = 
Charge on the plates of the capacitor, 
Now,
(A) To calculate the electric field strength, E when the separation distance, d = 1.00 mm =
:


(B) To calculate potential difference between the plates:

(C) Electric field strength when spacing is 2 mm, i.e.,
:

Since, the above expression of the electric field shows that it does not depend on the separation distance between the plates thus it will remain same, i.e., 
(D) Potential difference across the capacitor when d =
:
V = Ed = 
Answer:
the editor
Explanation:
the variable is usually a number, and the conditional loop has nothign to do with movement/ where something is located