Water (density p-1000 is discharging from through a hole at the bottom of a graduated 71 cylinder. The mass flow rate exiting th
e container may be approximated by: Where Cd is the dimensionless discharge coefficient, A, is the area of the discharge hole, g is the acceleration due to gravity, and y is the water height in the container. The diameter of the graduated cylinder is 8 cm.
For the following givens, use matlab or a spreadsheet to estimate the time to empty half the water from the container.
For partial credit, perform a simple calculation to estimate an amount of time known to be too short but greater than zero.
C,-0.6 2 ,-0.04 cm g 9.8 m/s/s
Yinitial20cm
For the following givens, use matlab or a spreadsheet to estimate the time to empty half the water from the container.
For partial credit, perform a simple calculation to estimate an amount of time known to be too short but greater than zero.
C,-0.6 2 ,-0.04 cm g 9.8 m/s/s
Yinitial20cm
1 answer:
You might be interested in
Answer:
The maximum water pressure at the discharge of the pump (exit) = 496 kPa
Explanation:
The equation expressing the relationship of the power input of a pump can be computed as:
where;
m = mass flow rate = 120 kg/min
the pressure at the inlet = 96 kPa
the pressure at the exit = ???
the pressure = 1000 kg/m³
∴
400000 = P₂ - 96000
400000 + 96000 = P₂
P₂ = 496000 Pa
P₂ = 496 kPa
Thus, the maximum water pressure at the discharge of the pump (exit) = 496 kPa
<u>Explanation:</u>
5 Horsepower for 30 mins,
(5)(745.7) = 3.7285 KW power delivered
General Efficiency of IC engine = 20%
Power required =
Energy required per week,
=P × Time = 18.64 × 60 × 30 = 33.5565 MJ
Lawn area = (30) (20) = 600
let sunlight hours be 8 hours
Hence, solar power input on lawn,
=5.62×3600 = 20232 kJ//day
energy input in lawn = (600) (20232) (7)
= 84974.4 mJ/week
Chemical efficiency by photosynthesis = 4%
Chemical content in grass = (84974.4) (0.04)
= 3398.97 mJ
Mass of the clippers
pounds
Removing water content,
dried grass clippings
= 11533.25 gallons
Trash cans repaired
By burning the gas, total energy input = 3398.97 MJ × 0.2
= 679.794 MJ
Efficiency of steeling engine = 20%
Energy output by engine = 679.794 ×0.2
= 135.96 mJ
Energy required by mover = 33.5565 mJ
Hence, Energy (output) ⇒ energy required