A 20-mm thick draw batch furnace front is subjected to uniform heat flux on the inside surface, while the outside surface is sub
1 answer:
Answer:
hello your question is incomplete attached below is the complete question
<em>answer</em> :
To ( inside temperature ) = 598 K
TL ( outside temperature ) = 594 k
Explanation:
a) Determine the surface temperature To and TL based on the known conditions provided in the drawing
To ( inside temperature ) = 598 K
TL ( outside temperature ) = 594 k
attached below is the detailed solution
You might be interested in
Answer:
γ =0.01, P=248 kN
Explanation:
Given Data:
displacement = 2mm ;
height = 200mm ;
l = 400mm ;
w = 100 ;
G = 620 MPa = 620 N//mm²; 1MPa = 1N//mm²
a. Average Shear Strain:
The average shear strain can be determined by dividing the total displacement of plate by height
γ = displacement / total height
= 2/200 = 0.01
b. Force P on upper plate:
Now, as we know that force per unit area equals to stress
τ = P/A
Also, τ = Gγ
By comapring both equations, we get
P/A = Gγ ------------ eq(1)
First we need to calculate total area,
A = l*w = 400 * 100= 4*10^4mm²
By putting the values in equation 1, we get
P/40000 = 620 * 0.01
P = 248000 N or 2.48 *10^5 N or 248 kN
Answer:
The answer is " and 157.5 MPa".
Explanation:
In point A:
The strength of its products with both the grain dimension is linked to this problem. This formula also for grain diameter of 310 MPA is represented as its low yield point
Here y is MPa is low yield point, x is mm grain size, and k becomes proportionality constant.
Replacing the equation for each condition:
People can get yo = 275 MPa with both equations and k= 15.5 Mpa .
To substitute the answer,
In point b:
The equation is
equation is:
by putting the above value in the formula we get the value that is= 157.5 MPa