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myrzilka [38]
3 years ago
10

How many liters would I need to make a 4M KCl solution using 8 moles of KCI?

Chemistry
1 answer:
hammer [34]3 years ago
5 0
M=n/v
4=8/v
4v=8
v=2
I don’t know which units you were given
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Question 4 (higher question)
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8 0
3 years ago
In order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00kg o
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M = amount of the solute  / mass of the <span>solvent

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molar mass KI = </span><span>166.0028 g/mol
</span><span>
Mass = 1,046 * 166.0028

Mass </span>≈<span> 173.63 g

hope this helps!

</span>
6 0
3 years ago
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