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Nana76 [90]
4 years ago
14

Which of the following elements would be predicted to be the best conductor of electricity? sodium (Na) germanium (Ge) sulfur (S

) neon (Ne)
Chemistry
2 answers:
lubasha [3.4K]4 years ago
4 0
Na because its a metal. Metals are the best conductors. S and Ne are nonmetals. and Ge is a metalloid. (Metalloids are semi conductors)
pentagon [3]4 years ago
4 0

The correct option is SODIUM, Na.

Out of all the options given above, it is only sodium that is a metal, the other ones are non metals and metalloid. Generally, metals are good conductor of heat and electricity because they have electrons, which are able to move about and thus they are thus able to conduct electricity round a circuit. Metals are generally bonded together by strong metallic bonds so they have high melting and boiling points, which make them suitable as conductors.

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Explanation:

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The distribution of Na+ ions across a typical biological membrane is 10 mmol dm-3 inside the cell and 140 mmol dm-3 outside the
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Answer :  The value of \Delta G^o across the membrane is 6.80 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}\\\\\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

where,

\Delta G^o = standard Gibbs free energy  = ?

R = gas constant = 8.314 J/K.mol

T = temperature = 37^oC=273+37=310K

K_{eq}  = equilibrium constant

C_{in} = concentration inside the cell = 10mmol.dm^{3-}

C_{out} = concentration outside the cell = 140mmol.dm^{3-}

Now put all the given values in the above formula, we get:

\Delta G^o=-RT\times \ln (\frac{C_{in}}{C_{out}})

\Delta G^o=-(8.314J/K.mol)\times (310K)\times \ln (\frac{10mmol.dm^{3-}}{140mmol.dm^{3-}})

\Delta G^o=6.80\times 10^{3}J/mol=6.80kJ/mol

Thus, the value of \Delta G^o across the membrane is 6.80 kJ/mol

8 0
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A(n) ______ is a mixture that does not scatter light.
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Explanation:

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