3 years ago

In which object more force has to be applied to move in between two objects of mas 11

Physics

1 answer:

jeka943 years ago

4 0

Answer:

my butt

Explanation:

2x2 by the power of 10 divide that 98

You might be interested in

A satellite orbits earth at 800 m from the earth's center. Gravity at this location is 6.2 m/s^2. What is the velocity of the sa

oksano4ka [1.4K]

Recall that the magnitude of the acceleration $a$ of a particle moving with speed $v$ in a circular path around a point at a distance $R$ away from the particle is given by

$a=\dfrac{v^2}R$

So, the satellite has velocity

$6.2\,\dfrac{\rm m}{\mathrm s^2}=\dfrac{v^2}{800\,\rm m}\implies v=70.4\,\dfrac{\rm m}{\rm s}$

pointing in the direction tangent to the circular path.

6 0

3 years ago

A person standing waist-deep in a swimming pool appears to have short legs because of light

Rama09 [41]

Answer:

Explanation:

Refraction :)

8 0

3 years ago

A rock is thrown downward from the top of a cliff If the rock hits the ground after 2.0 s, with a velocity of 12 m/s what is the

expeople1 [14]

Explanation:

v = u + a t

12 = 0 + 2a

a= 12/2

a=6 m/s2

v^2 - u ^2 = 2 as

12 ^2 - 0 ^2 = 2 * 6 * s

144 = 12 s

s = 144/12

s = 12 m

8 0

3 years ago

A train moves from rest to a speed of 25 m/s in 50.0 seconds. What is its acceleration?

ELEN [110]

Answer:

Wellll. I am assuming the direction of speed is in the same direction as the direction of displacement of the train. (i.e. Velocity is positive)

Acceleration is defined as the rate of change of velocity with respect to time (m^s-2)

Explanation:

5 0

2 years ago

A 100-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope a

olchik [2.2K]

Answer:

The force required is equal to $30\pi N$ .

Explanation:

We know that

Torque = force × perpendicular distance

= F × R = I× $\alpha$

I = M× $\frac{R^{2} }{2}$

From above equation $\alpha = \frac{FR}{I}$ .............. 1

We know that

$w=w_{o} +\alpha t$ ...........................2

Given that t= 2 sec

$w_{o} = 0$

$w=0.4 rev/s = 0.8\pi rad/s$

From equation 1 and 2 , we get

F = $\frac{wI}{RT}$ = $\frac{w\times m \times r}{2t}$

Upon substituting the above values we will be getting

F = $30\pi N$

3 0

3 years ago