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Morgarella [4.7K]
3 years ago
8

When a horn is moving away from an observer the sound waves from it will pass by the observer____ frequently, causing the pitch

to____
Chemistry
1 answer:
xxMikexx [17]3 years ago
8 0
The answer: less frequency, causing the pitch to be lowered. 

This is known as the Doppler effect. When you have an object that is producing sound while moving, the side that it is moving towards to will have waves that will become a bit more squished together, while the other side that it is moving away from will have waves that are spaced a bit more apart from each other. The only determining factor in this is the magnitude of the speed, so the faster the object is moving towards or away from you, then the more severe pitch change the object will have.
In this case, it's just asking in general what would happen if the horn was moving away from you while it was giving off sound waves. Therefore, since it is moving away from you, its sound waves are a bit further apart, resulting in a lowered frequency and pitch.
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11. What is the specific heat of a substance with a mass of 25.5 g that requires 412 J
Romashka-Z-Leto [24]

Answer:

297 J

Explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

6 0
3 years ago
How do you convert volume to moles at STP?
Vanyuwa [196]

The conversion of volume to moles at STP is 1 mole.

The ideal gas equation is given as :

P V = n R T

where,

P = pressure of the gas

V = volume of the gas

n = ?

R = constant = 0.823 atm L / mol K

T = temperature

At STP , the pressure is 1 atm and the temperature is 273.15 K, the volume At STP is 22.4 L.

moles , n = P V / R T

n = ( 1 × 22.4 ) / (0.0823 × 273.15)

n = 1 mole

Thus, at STP , the number of moles is 1 mol.

To learn more about moles here

brainly.com/question/8429153

#SPJ4

6 0
1 year ago
What general trend applies to solubility?
Marysya12 [62]

Answer:

Basically, solubility increases with temperature. It is the case for most of the solvents. The situation is though different for gases. With increase of the temperature they became less soluble in each other and in water, but more soluble in organic solvents.

5 0
3 years ago
3. How many formula units of NaOH are in 0.87 moles?
Lady_Fox [76]

Answer: 1 mole of H2O= about 1/3 of a cup (18 mL). It is helpful ... 6.02 x 1023 H2O molecules. = 6.02 x 1023 NaCl formula unit. 1 mole C. 1 mole H2O. 1 mole

Explanation:

5 0
2 years ago
Bond length is the distance between the centers of two bonded atoms. On the potential energy curve, the bond length is the inter
mariarad [96]

Answer:

152 pm

Explanation:

According to the question, we can estimate the bond length from the given values of the atomic radii. This now is the upper limit of the bond length for the molecule.

Since we have that;

Atomic radius of H= 37.0 pm

Atomic radius of Br = 115.0 pm

Bond length = Atomic radius of H + Atomic radius of Br

Bond length = 37.0 pm + 115.0 pm

Bond length = 152 pm

5 0
2 years ago
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