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REY [17]
3 years ago
11

If you have a 8.6 mol of AlCl3 in a 6.8 M solution, how many Liters does it make?

Chemistry
1 answer:
Nana76 [90]3 years ago
7 0

Answer: 1.3 L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the volume for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{moles of solute}}{\text{Volume of solution in L}}

6.8M=\frac{8.6mol}{\text{Volume of solution in L}}

\text{Volume of solution in L}=1.3

Thus the volume in Liters is 1.3

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The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl
nevsk [136]

Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of  caffeine extracted is  P =  39.8 \ mg

Explanation:

From the question above  we are told that

    The  K value is  K =  4.6

     The  mass of the caffeine is  m  = 40 mg

      The  volume of water is  V  = 2 mL

      The volume  of caffeine is  v_c =  2 mL

     The number of times the extraction was done is  n =  3

Generally the mass of  caffeine that will be  extracted is  

           P =  m  *  [\frac{V}{K *  v_c + V} ]^3

substituting values  

           P =  40   *  [\frac{2}{4.6 *  2 + 2} ]^3

           P =  39.8 \ mg

6 0
3 years ago
A force of 20 N acts upon 5 kg block caculate the accerleration of the object
Vedmedyk [2.9K]

Answer:

\boxed{\text{4 m $\cdot$ s$^{-2}$}}

Explanation:

F = ma

a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}

 

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bottom right top left fig

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Answer:

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Explanation:

iodous acid would also be known as HIO2

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