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3 years ago

HELP ME!!! What is the gravitational potential energy of a 200 Kg wrecking ball that is held up 25 m off the ground?

Chemistry

1 answer:

melomori [17]3 years ago

3 0

Answer:

It can be number 3

Explanation:

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Is this equation balanced? nh4oh+hc2h3o2=nh4c2h3o2+h2o

Usimov [2.4K]

Answer:

It IS balanced

Explanation:

3 0

3 years ago

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Which quantity does a light-year measure? A) distance B) speed C) time D) volume

tatuchka [14]

Answer:

speed

Explanation:

6 0

3 years ago

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The decomposition of N_2O_5(g) following 1st order kinetics. N_2O_5(g) to N_2O_4(g) + ½ O_2(g) If 2.56 mg of N_2O_5 is initially

Crank

Answer: The rate constant is $0.334s^{-1}$

Explanation ;

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 4.26 min

a = initial amount of the reactant = 2.56 mg

a - x = amount left after decay process = 2.50 mg

Now put all the given values in above equation to calculate the rate constant ,we get

$4.26=\frac{2.303}{k}\log\frac{2.56}{2.50}$

$k=\frac{2.303}{4.26}\log\frac{2.56}{2.50}$

$k=5.57\times 10^{-3}min^{-1}=5.57\times 10^{-3}\times 60s^{-1}=0.334s^{-1}$

Thus rate constant is [tex]0.334s^{-1}

4 0

3 years ago

I AM SO STUCK!

ankoles [38]

1kg is about 2.2 pounds. So 4kg = 8.8 pounds. If that represent 19% of the total, here is the answer.
0.19*x=8.8
x=8.8/0.19
x=46.31 pounds

3 0

3 years ago

A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6

joja [24]

Answer: The concentration of $CH_3COOH$ comes out to be 0.16 M.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $CH_3COOH$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL$

Putting values in above equation, we get:

$1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M$

Hence, the concentration of $CH_3COOH$ comes out to be 0.1862 M.

4 0

3 years ago