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3 years ago

7

Which number line model represents the expression -2/5 + 4/5

1 answer:

Akimi4 [234]3 years ago

5 0

Hi

-2/5 + 4/5 = 2/5..................

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iragen [17]

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=7.2\\ b=6.7\\ c=4.5\\ s=\frac{7.2+6.7+4.5}{2}\\[0.5em] \qquad 9.2 \end{cases} \\\\\\ A\sqrt{9.2(9.2-7.2)(9.2-6.7)(9.2-4.5)}\implies A=\sqrt{9.2(2)(2.5)(4.7)} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A\approx 14.704~\hfill$

4 0

3 years ago

Please help D:<br> mathswatch question

algol13

Answer:

first you have to find the values of the two sides of the rectangle. BC=5 cm

Area of a trapezium

= 1/2 x (5+9) x (11-5)

= 42 cm^2

4 0

3 years ago

1. Identify the vertex and the y-intercept of the graph of the function y=-2(x+ 2)+2.

KATRIN_1 [288]

Answer:

Please let me know if your quadratic is $y=-2(x+2)^2+2$ .

And if so your vertex is (-2,2) and your y-intercept is (0,-6)

Step-by-step explanation:

It says vertex so I'm thinking you meant $y=-2(x+2)^2+2$ . Please correct me if I'm wrong.

The vertex form of a quadratic is $y=a(x-h)^2+k$ . It is called that because it tells you the vertex (h,k).

So if you compare the two forms you should see -h=2 while k=2.

-h=2 implies h=-2.

So the vertex is (h,k)=(-2,2).

To find the y-intercept, set x=0 and find y.

$y=-2(0+2)^2+2$

$y=-2(2)^2+2$

$y=-2(4)+2$

$y=-8+2$

$y=-6$

So the y-intercept is (0,-6).

7 0

3 years ago

4x-6y=18 solve for y

igor_vitrenko [27]

Answer:

y= -3 + 2x/3

Step-by-step explanation:

move all terms that dont contain y to the right side and solve

Hope this helps! have a nice day! Please consider making me Brainliest!

6 0

4 years ago

If f(x) = 6 what is x?

Margarita [4]

Answer:well you don't have x because x would be 1

5 0

3 years ago