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natulia [17]
3 years ago
8

Sonia O'Sullivan of Ireland set the World Record in 1994 for the Women's 1000 m race with a time of 2 minutes and 45 seconds. Wh

at was her average velocity?​ ill give brainliest
Physics
2 answers:
Aleks04 [339]3 years ago
5 0

Answer:

Sonia O'Sullivan (born 28 November 1969) is an Irish former track and field athlete. She won a gold medal in the 5000 metres at the 1995 World Championships, and a silver medal in the 5000 metres at the 2000 Olympic Games.[1] Her 2000 m world record of 5:25.36, set in 1994 stood until 2017.[2]

O'Sullivan first came to prominence when winning the 1500 m at the 1991 Universiade, before going on to finish fourth in the 3000 m final at the 1992 Olympic Games. She then won a silver medal in the 1500 m at the 1993 World Championships. She was the favourite for the 5000 m title at the 1996 Olympic Games but dropped out of the final due to illness. As well as her 1995 World title, she won three gold medals at the European Championships, in the 3000 m (1994), 5000 m (1998) and 10,000 m (1998), and is a two-time World Cross Country Champion.

O'Sullivan won silver medals in the 5000 m and 10,000 m at the 2002 European Championships, and competed at her fourth Olympic Games in 2004. She is known for her dramatic kick, clocking 28-second final 200 m splits in some of her races.[3]

She is the one of two women (the other Tirunesh Dibaba) who won the short and long course World Cross Country title at the same championship (1998 in Marrakesh).[4]

you can find from here

puteri [66]3 years ago
5 0

Answer:

6.06061 m/s

Explanation:

1000 m in 165sec

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Calculate the speed of an object that tavels 62.43m in 38.4s
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A child sleds down a hill with an acceleration of 2.94 m/s2. If her initial speed is 0.0 m/s and her final speed is 17.5 m/s, ho
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Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial (v_{o}) and final speeds (v_{f}), measured in meters per second, and acceleration (a), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom (t), measured in seconds, is:

t = \frac{v_{f}-v_{o}}{a} (1)

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 17.5\,\frac{m}{s} and a = 2.94\,\frac{m}{s^{2}}, then the time taken is:

t = \frac{17.5\,\frac{m}{s}-0\,\frac{m}{s} }{2.94\,\frac{m}{s^{2}} }

t = 5.952\,s

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

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