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sergeinik [125]
3 years ago
14

During a circus performance, a 71.2-kg human cannonball is shot out of an 18.0-m-long cannon. If the human cannonball spends 0.7

85 s in the cannon, determine the average net force exerted on him in the barrel of the cannon. (Assume the acceleration is constant.)
Physics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

F=ma = 71.2 * 58.42 = 4159.5 N

Explanation:

for FORCE we need a: acceleration (F=ma)

for acceleration we can apply the second equation of motion

s = ut + 0.5at^2

where

s = 18 m ( displacement)

u = 0 m/s (initial velocity)

t = 0.785 s (time)

18 = 0.5 * a * (0.785)^2

a = 58.42 m/s^2

now

F=ma = 71.2 * 58.42 = 4159.5 N

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A positive charge of 3.2 x 10 -5 C is located 0.85 m away from another positive charge of 7.4 x 10 -6 C. What is the electric fo
zmey [24]

by using Coulumbs Law its 2.95N.

7 0
3 years ago
If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s = 80t − 16t 2 . (a) what
MAXImum [283]
Max height occurs when v = 0.
v(t) = ds(t)/dt
v(t) = 80 - 32t
0 = 80 - 32t
t = 5/2

s(5/2) = 80(5/2) - 16(5/2)^2
s(5/2) = 100
Answer: 100 ft

96 = 80t - 16t²
t = 3, 2
(80 ± √256) / 32 using the quadratic equation.

v(2) = 16
v(3) = -16
4 0
2 years ago
3. If a voltage difference of 3.0 V causes a
MAXImum [283]

Answer:

it will be 1.8. voltage

that is wat I can't say

5 0
2 years ago
Needddd helppppppp!!!
yulyashka [42]

Answer:

2/9 times as strong.

Explanation:

From the question given above, the following assumptions were made:

Initial mass of 1st planet (M₁ ) = M

Initial mass of 2nd planet (m₁ ) = m

Initial distance apart (r₁) = r

Initial Force of attraction (F₁) = F

Final mass of 1st planet (M₂) = 2M

Final mass of 1st planet (m₂) = constant = m

Final distance apart (r₂) = 3r

Final force of attraction (F₂) =?

Next, we shall obtain an expression to determine the new force. This can be obtained as follow:

F = GMm / r²

Cross multiply

Fr² = GMm

Divide both side by Mn

G = Fr² / Mm

Since G is constant, then we have

F₁r₁² / M₁m₁ = F₂r₂² / M₂m₂

Finally, we shall determine the new force as follow:

Initial mass of 1st planet (M₁ ) = M

Initial mass of 2nd planet (m₁ ) = m

Initial distance apart (r₁) = r

Initial Force of attraction (F₁) = F

Final mass of 1st planet (M₂) = 2M

Final mass of 1st planet (m₂) = constant = m

Final distance apart (r₂) = 3r

Final force of attraction (F₂) =?

F₁r₁² / M₁m₁ = F₂r₂² / M₂m₂

Fr² / Mm = F₂ × (3r)² / 2M × m

Fr² / Mm = F₂ × 9r² / 2Mm

Cross multiply

Fr² × 2Mm = F₂ × 9r² × Mm

Divide both side by 9r² × Mm

F₂ = Fr² × 2Mm / 9r² × Mm

F₂ = F × 2 / 9

F₂ = 2/9 F

Thus, the new force is 2/9 times the original force i.e 2/9 times as strong.

4 0
3 years ago
Which produces more carbon dioxide?
Serhud [2]
It depends on the car and the home and what it is producing but most commonly it would be cars producing more carbon dioxide.
6 0
3 years ago
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