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sergeinik [125]
2 years ago
14

During a circus performance, a 71.2-kg human cannonball is shot out of an 18.0-m-long cannon. If the human cannonball spends 0.7

85 s in the cannon, determine the average net force exerted on him in the barrel of the cannon. (Assume the acceleration is constant.)
Physics
1 answer:
Sophie [7]2 years ago
7 0

Answer:

F=ma = 71.2 * 58.42 = 4159.5 N

Explanation:

for FORCE we need a: acceleration (F=ma)

for acceleration we can apply the second equation of motion

s = ut + 0.5at^2

where

s = 18 m ( displacement)

u = 0 m/s (initial velocity)

t = 0.785 s (time)

18 = 0.5 * a * (0.785)^2

a = 58.42 m/s^2

now

F=ma = 71.2 * 58.42 = 4159.5 N

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2.7549 x 10^4 is the answer I hope this helped u
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2 years ago
A basketball leaves a player's hands at a height of 2.00 m above the floor. The basket is 3.05 m above the floor. The player lik
shutvik [7]

Answer:(10.69, 11.436)

Explanation:

Given

initial height of ball is 2 m

height of basket is 3.05 m

Launching angle=40^{\circ}

x =12\pm 0.27

y=1.05

equation of trajectory of ball is given by

y=xtan\theta -\frac{gx^2}{2u^2cos^2\theta }

for x=12.27

1.05=12.27\times tan40-\frac{g12.27^2}{2u^2cos^{2}40 }

u=10.69

for x=11.73

1.05=11.73\times tan40-\frac{g11.73^2}{2u^2cos^{2}40 }

u=11.436 m/s

Thus range of speed is (10.69, 11.436)

3 0
2 years ago
A sheet of aluminum with a rectangular shape is attached to a vertical support by a set of hinges. Assume the sheet is uniform a
Ivenika [448]
Hey I just got home
6 0
2 years ago
A 57-kg woman holds a 6-kg package as she stands within an elevator which briefly accelerates upward at a rate of 0.15g. Determi
Temka [501]

Answer:

R = 710.7N

L = 67.689 N

During gravity fall L = R = 0 N

Explanation:

So the acceleration that the elevator is acting on the woman (and the package) in order to result in a net acceleration of 0.15g is

g + 0.15g = 1.15g

The force R that the elevator exerts on her feet would be product of acceleration and total mass (Newton's 2nd law):

a(m + M) = 1.15g(57 + 6) = 1.15*9.81*63 = 710.7N

The force L that she exerts on the package would be:

am = 1.15g *6 = 1.15*9.81*6 = 67.689N

When the system is falling, all have a net acceleration of g. So the acceleration that the elevator exerts on the woman (and the package) is 0, and so are the forces L and R.

7 0
3 years ago
If 41.5 mol of an ideal gas occupies 86.5 L at 27.00 °C, what is the pressure of the gas?
Dmitry [639]
PV=nRT
(P)(86.5)=(41.5)(.08206)(300.15)
(P)(86.5)=(1022.157824)
P=11.81685345 atm
7 0
3 years ago
Read 2 more answers
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