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sergeinik [125]
3 years ago
14

During a circus performance, a 71.2-kg human cannonball is shot out of an 18.0-m-long cannon. If the human cannonball spends 0.7

85 s in the cannon, determine the average net force exerted on him in the barrel of the cannon. (Assume the acceleration is constant.)
Physics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

F=ma = 71.2 * 58.42 = 4159.5 N

Explanation:

for FORCE we need a: acceleration (F=ma)

for acceleration we can apply the second equation of motion

s = ut + 0.5at^2

where

s = 18 m ( displacement)

u = 0 m/s (initial velocity)

t = 0.785 s (time)

18 = 0.5 * a * (0.785)^2

a = 58.42 m/s^2

now

F=ma = 71.2 * 58.42 = 4159.5 N

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The speed of sound through diamond is about 12,000 m/s. The speed of sound through wood is about 3,300 m/s. Which statement expl
iris [78.8K]

Answer: They have different rigidities.

Explanation:

3 0
3 years ago
Two forces are acting on an object, but the net force on the object is O N. For the net
Alenkinab [10]

Answer:

  A.  The forces are the same size and in opposite directions.

Explanation:

Just as an opposite number will cancel a number: -1 +1 = 0, so an opposite force will cancel a force, with the result that the net is zero.

6 0
3 years ago
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A 4kg box is pressed into a spring. The spring constant k=220N/m. The box is released at the bottom of a frictionless ramp and r
AVprozaik [17]

Answer:

Explanation:

The stored elastic energy in the spring helps the box to rise to a height of .75 m

So stored elastic energy = potential energy attained

1/2 k d² = mgh , k is spring constant , d is compression in spring , m is mass of box , h is height attained .

Putting the values

.5 x 220 x d² = 4 x 9.8 x .75

d² = .2673

d = .517 m

51.7 cm .

8 0
3 years ago
Read 2 more answers
As a consultant to the soft-drink industry, Dr. J is given the task of conducting the ultimate Pepsi taste test. This is Dr. J's
dem82 [27]

Answer:

A) How much work does the Pepsi do on the bullet = 0.0625J

B) At what velocity does the Pepsi hit the floor = 7.67m/s

Explanation:

  • Given mass of bullet = 5g
  • initial velocity = 500 m/sec
  • final velocity = 5 m/sec

From work done = Force X Distance

  • WD = Mad
  • a = v - u /t

Workdone ; m(v - u )/t

A) The work done by the Pepsi is equal to the change in kinetic energy while in the Pepsi:

  • but The work done by the container wall on the bullet is equal to the change in kinetic energy on either side of the wall: W = change in kinetic energy = 1/2 mv²

= 1/2 X 0.005 x 500² - 1/2 X 0.055 x 5²

= 624.94J

  • Therefore ; The work done by the Pepsi is equal to the change in kinetic energy while in the Pepsi = W = change in KE = 0.0625 - 0 = 0.0625J

B) At what velocity does the Pepsi hit the floor?

  • From conservation of energy principle; PE = KE
  • mgh = 1/2mv²
  • 0.98 X 3 = 1/2v²
  • velocity = 7.67m/s

3 0
3 years ago
Calculate kinetic energy of an 86kg scooter moving at 18 m/s
myrzilka [38]

Calculate the kinetic energy of an 86-kg scooter moving at 18 m/s?

K.E.      =      (1/2)mv^2

K.E.      =        (1/2)86   *   18^2

K.E.       =         (Answer  Unit)     =====>    J

M     =      86kg

V      =        18 m/s

Significant Figures  ======>    6

Answer:   ======>   KE     =      13932 J



Show work:

1/2  *    86   *   18^2

(1/2)86  *  18^2

Remove Parenthesis:      

a        =       a

1/2 *  86  *  18^2

Multiply Fractions:

a * b/c     =    a  *  b/c

=     1  *  86  *  18^2/2

Multiply the numbers:

1  *  86     =     86

18^2    *    86/2

Divide the numbers:

86/2     =     43

18^2   *    43

18^2     =     324

43    *    324

Multiply the numbers:

43   *    324

13932

Therefore,  Your answer   is    KE    =     13932 J



Hope that helps!!!!                                   : )  sorry for the long explanation!!!








7 0
3 years ago
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