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maxonik [38]
3 years ago
12

Coherent light of frequency 6.32 x 1014 Hz passes through two thin slits and falls on a screen 85.0 cm away. You observe that th

e third bright fringe occurs at ±3.11 cm on either side of the central bright fringe.
(a) How far apart are the two slits?
(b) At what distance from the central bright fringe will the third dark fringe occur?
Physics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

HE WAS GRIPPING ONBACKWHILE HE EAT UP DIS CAT

Explanation:

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2 rocks of different masses roll down a hill at the same speed which rock has more kinetic energy small one or big one ???
Sophie [7]

Kinetic energy depends on the mass and the speed of a moving object.

If the speeds are equal, then the rick with more mass has more kinetic energy.

5 0
2 years ago
Read 2 more answers
Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector
Sav [38]
Good morning.

We see that \mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}

The magnitude(norm, to be precise) can be calculated the following way:

\star \ \boxed{\mathsf{\overset{\to}{a}=(x, y,z)\Rightarrow ||\overset{\to}{a}|| = \sqrt{x^2+y^2+z^2}}}


Now the calculus is trivial:

\mathsf{\|\overset{\to}{b} \| =\sqrt{4^2+4^2+2^2} =\sqrt{16+16+4}}\\ \\ \mathsf{\|\overset{\to}{b}\|=\sqrt{36}}\\ \\ \boxed{\mathsf{\|\overset{\to}{b}\| = 6.00 \ u}}
7 0
3 years ago
While driving on a highway, your HMMWV starts to pull to one side. You stop and check your tires – one tire is going flat. There
MrRissso [65]

Answer:

30 miles people hour (mph)

Explanation:

The maximum speed for one flat tyre is 30mph, for both tyres it is 20 mph and for two tyres on the same side it is 30mph. When a tyre is punctured driving at high speed should be avoided and not too long distance should be covered to avoid further accident and for the safety of other vehicles. Speed limit and distance for flat tires should be strictly followed.

3 0
3 years ago
To get to your baseball game, you had to drive 2 kilometers north, then 5 kilometers west, and finally 2 kilometers south. What
Vesna [10]
Answer is C. 5 km west
7 0
2 years ago
The magnitude of the magnetic field B a distance r from a long straight wire is B = μ 0 I 2 π r where μ 0 is the permeability co
PSYCHO15rus [73]

Answer:

The magnetic field is lowest for largest distance and highest when distance is least.

Explanation:

The magnitude of magnetic field strength at a distance 'r' from a long straight wire carrying current 'I' is given as:

B=\frac{\mu_0 I}{2\pi r}\\Where,\mu_0\to permeability\ constant\ of\ free\ space

Now, as per question, the distance 'r' is varied while keeping the current constant in the wire.

As seen from the above formula, the magnitude of magnetic field strength for a constant current varies inversely with the distance 'r'. This means that, as the value of 'r' increases, the magnitude of magnetic field strength decreases and vice-versa.

Therefore, the magnitude of magnetic field strength is maximum when the distance 'r' is least and the magnetic field is minimum for the largest distance.

Example:

If B_1, B_2,\ and\ B_3 are the magnitudes of magnetic field strengths for distances r_1,r_2, \ and\ r_3 respectively such that r_1. Now, as per the explanation above, the order of magnitudes of magnetic field strength is:

B_1>B_2>B_3

6 0
3 years ago
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