Answer:
the final velocity of the bus is -20 m/s.
Explanation:
Given;
initial velocity of the bus, u = 20 m/s
deceleration of the bus, -a = 8 m/s²
time of motion, t = 5 s
The final velocity of the bus is calculated as;
v = u + at
v = 20 + (-8 x 5)
v = 20 - 40
v = -20 m/s.
Therefore, the final velocity of the bus is -20 m/s.
1) Let's call

the speed of the southbound boat, and

the speed of the eastbound boat, which is 3 mph faster than the southbound boat. We can write the law of motion for the two boats:


2) After a time

, the two boats are

apart. Using the laws of motion written at step 1, we can write the distance the two boats covered:


The two boats travelled in perpendicular directions. Therefore, we can imagine the distance between them (45 mi) being the hypotenuse of a triangle, of which

and

are the two sides. Therefore, we can use Pythagorean theorem and write:

Solving this, we find two solutions. Discarding the negative solution, we have

, which is the speed of the southbound boat.
Answer:
2. The velocity of the particle is tangent to the circle
Explanation:
1. The velocity of the particle is constant.
Incorrect
Reason : Since the tangential speed is not constant, hence the velocity of the particle is not constant.
2. The velocity of the particle is tangent to the circle.
Correct
Reason : In circular motion, the direction of velocity is always given by the tangent to the circle.
3. The acceleration of the particle is constant.
Incorrect
Reason : The tangential speed of the particle is not constant which in turn keeps changing the centripetal acceleration of the particle. hence the acceleration of the particle is not constant.
4. The acceleration of the particle is toward the center of circle.
Incorrect.