Answer:
volumetric flow rate = 
Velocity in pipe section 1 = 
velocity in pipe section 2 = 12.79 m/s
Explanation:
We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.
The density of water is = 997 kg/m³
density = mass/ volume
since we are given the mass, therefore, the volume will be mass/density
25/997 = 
volumetric flow rate = 
Average velocity calculations:
<em>Pipe section A:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

<em>Pipe section B:</em>
cross-sectional area =

mass flow rate = density X cross-sectional area X velocity
velocity = mass flow rate /(density X cross-sectional area)

Answer:
a) 
b) 
Explanation:
From the question we are told that:
Cast-iron block Dimension:
Length
Width 
Feed
Depth 
Diameter 
Number of cutting teeth 
Rotation speed 
Generally the equation for Approach is mathematically given by



Therefore
Effective length is given as



a)
Generally the equation for Machine Time is mathematically given by

Where



Therefore


b)
Generally the equation for Material Removal Rate. is mathematically given by



Answer:
it is not possible to place the wires in the condui
Explanation:
given data
total area = 2.04 square inches
wires total area = 0.93 square inches
maximum fill conduit = 40%
to find out
Can it is possible place wire in conduit conduit
solution
we know maximum fill is 40%
so here first we get total area of conduit that will be
total area of conduit = 40% × 2.04
total area of conduit = 0.816 square inches
but this area is less than required area of wire that is 0.93 square inches
so we can say it is not possible to place the wires in the conduit
(a) The number of vacancies per cubic centimeter is 1.157 X 10²⁰
(b) ρ = n X (AM) / v X Nₐ
<u>Explanation:</u>
<u />
Given-
Lattice parameter of Li = 3.5089 X 10⁻⁸ cm
1 vacancy per 200 unit cells
Vacancy per cell = 1/200
(a)
Number of vacancies per cubic cm = ?
Vacancies/cm³ = vacancy per cell / (lattice parameter)³
Vacancies/cm³ = 1 / 200 X (3.5089 X 10⁻⁸cm)³
Vacancies/cm³ = 1.157 X 10²⁰
Therefore, the number of vacancies per cubic centimeter is 1.157 X 10²⁰
(b)
Density is represented by ρ
ρ = n X (AM) / v X Nₐ
where,
Nₐ = Avogadro number
AM = atomic mass
n = number of atoms
v = volume of unit cell
Answer:
(Option B)
Explanation:
The absolute pressure of the air-filled tank is:

