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umka21 [38]
3 years ago
6

Help me

Physics
1 answer:
Anni [7]3 years ago
7 0

Answer:

.

Explanation:

,.....................................

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Yall is this right
Aleksandr [31]

Answer:

(A)

Explanation:

ITS A ok ok bye

3 0
2 years ago
Kindly answer the question about Work and Power. Image is attached below.
natita [175]

Answer:

89600 Watts.

Explanation:

From the question given above, the following data were obtained:

Mass (m) of speedboat = 2800 Kg

Initial velocity (u) = 0 m/s

Final velocity (v) = 16 m/s

Time (t) = 8 s

Power (P) expended by the speedboat =?

Next, we shall determine the acceleration of the speedboat. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 16 m/s

Time (t) = 8 s

Acceleration (a) =?

v = u + at

16 = 0 + (a × 8)

16 = 0 + 8a

16 = 8a

Divide both side by 8

a = 16/8

a = 2 m/s²

The acceleration of the speedboat is 2 m/s²

Next, we shall determine the force exerted by the speedboat. This can be obtained as follow:

Mass (m) of speedboat = 2800 Kg

Acceleration (a) of speedboat = 2 m/s²

Force (F) of speedboat =?

F = ma

F = 2800 × 2

F = 5600 N

Finally, we shall determine the expended by the speedboat at maximum speed. This can be obtained as follow:

Force (F) of speedboat = 5600 N

Maximum velocity (v) = 16 m/s

Power (P) expended by the speedboat =?

P = F × v

P = 5600 × 16

P = 89600 Watts

Thus, the power expended by the speedboat is 89600 Watts.

4 0
3 years ago
Which of the following pure elements exist as liquids at normal Earth temperatures?
belka [17]

Answer:

The only liquid elements at standard temperature and pressure are bromine (Br) and mercury (Hg).

6 0
3 years ago
Read 2 more answers
How do you solve e from the equation f=e/s
Andrej [43]
1738 Fetty wap bhsyfnd hdnchd hand hdnzudnusjd jdnshdkdndb hdkcnd
7 0
3 years ago
A force F→=(cx-3.00x2)iˆ acts on a particle as the particle moves along an x axis, with F→ in newtons, x in meters, and c a cons
DerKrebs [107]

Answer:

Explanation:

Work done = ∫Fdx

= ∫(cx-3.00x²)   dx

[ c x² / 2 - 3 x³ / 3 ]₀²

= change in kinetic energy

= 11-20

= - 9 J

[ c x² / 2 -  x³   ]₀² = - 9

c x 2² / 2 - 2³ = -9

2c - 8 = -9

2c = -1

c = - 1/2

6 0
4 years ago
Read 2 more answers
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