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dmitriy555 [2]
2 years ago
15

Question 4 (5 points)

Physics
2 answers:
Andreas93 [3]2 years ago
6 0

Answer:

kajsskskw जिम्मेवार द्वन्द्वका दिदीबहिनी दिनेश दिनेश दिनु सायदै दिनेश दिनु दिनु द्वन्द्वका दिनु

dybincka [34]2 years ago
5 0

Answer:

CₙH₂ₙ

Explanation:

Alkenes have at least one double bond between 2 of the parent chain carbons. If the general formula for alkanes (no double bonds) is CₙH₂ₙ₊₂, it makes sense that the general formula for alkenes is CₙH₂ₙ. This means that alkenes have 2 less hydrogens than their alkane counterparts.

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To maintain your body temperature your body converts chemical potential energy into thermal energy true or false
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4 years ago
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If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?
Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

y=y_{o}+V_{oy}t-\frac{g}{2}t^{2} (1)

Where:

y=0 is the final height of the ball

y_{o}=h is the initial height of the ball

V_{oy}=V_{o}sin(0\°)=0 is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

t=0.5 s is the time at which the ball lands

g=9.8 m/s^{2} is the acceleration due gravity

So, with these conditions the equation is rewritten as:

h=\frac{g}{2}t^{2} (2)

h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2} (3)

Finally:

h=1.22 m

4 0
3 years ago
A shell is fired with a horizontal velocity in the positive x direction from the top of an 80 m high cliff. The shell strikes th
Sonbull [250]

Answer:

V = 331.59m/s

Explanation:

First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.

S = ut + 1/2at²

Given height of the cliff S = 80m

initial velocity u = 0m/s²

a = g = 9.81m/s²

Substitute

80 = 0+1/2(9.81)t²

80 = 4.905t²

t² = 80/4.905

t² = 16.31

t = √16.31

t = 4.04s

Next is to get the vertical velocity

Vy = u + gt

Vy = 0+(9.81)(4.04)

Vy = 39.6324

Also calculate the horizontal velocity

Vx = 1330/4.04

Vx = 329.21m/s

Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.

V² = Vx²+Vy²

V² = 329.21²+39.63²

V² = 329.21²+39.63²

V² = 108,379.2241+1,570.5369

V² = 109,949.761

V = √ 109,949.761

V = 331.59m/s

Hence the speed of the shell as it hits the ground is 331.59m/s

7 0
3 years ago
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6 0
3 years ago
A particular spring has a spring constant of 25 N/m.
kotegsom [21]

Answer:

<h2>2.8×10^-3</h2>

e.p.e =  \frac{1}{2} k {x}^{2}   \\   = \frac{1}{2}  \times 25 \times (0.015m)^{2}  \\  = 0.0028125

<u>0.0028125N</u><u> </u>

8 0
3 years ago
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