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Inga [223]
2 years ago
9

Help! I need help on how to do these problems.

Chemistry
1 answer:
svetlana [45]2 years ago
6 0

Answer:

a. 3; b. 5; c. 10; d. 12

Explanation:

pH is defined as the negative log of the hydronium concentration:

pH = -log[H₃O⁺] (hydronium concentration)

For problems a. and b., HCl and HNO₃ are strong acids. This means that all of the HCl and HNO₃ would ionize, producing hydronium (H₃O⁺) and the conjugate bases Cl⁻ and NO₃⁻ respectively. Further, since all of the strong acid ionizes, 1 x 10⁻³ M H₃O⁺ would be produced for a., and 1.0 x 10⁻⁵ M H₃O⁺ for b. Plugging in your calculator -log[1 x 10⁻³] and -log[1.0 x 10⁻⁵] would equal 3 and 5, respectively.

For problems c. and d. we are given a strong base rather than acid. In this case, we can calculate the pOH:

pOH = -log[OH⁻] (hydroxide concentration)

Strong bases similarly ionize to completion, producing [OH⁻] in the process; 1 x 10⁻⁴ M OH⁻ will be produced for c., and 1.0 x 10⁻² M OH⁻ produced for d. Taking the negative log of the hydroxide concentrations would yield a pOH of 4 for c. and a pOH of 2 for d.

Finally, to find the pH of c. and d., we can take the pOH and subtract it from 14, giving us 10 for c. and 12 for d.

(Subtracting from 14 is assuming we are at 25°C; 14, the sum of pH and pOH, changes at different temperatures.)

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Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur
Marina CMI [18]

Answer : The mass of water produced will be 32.78 grams.

Explanation : Given,

Mass of C_5H_{12} = 21.9 g

Molar mass of C_5H_{12} = 72.15 g/mole

Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of C_5H_{12}.

\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles

Now we have to calculate the moles of H_2O.

The balanced chemical reaction will be,

C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)

From the balanced reaction we conclude that

As, 1 mole of C_5H_{12} react to give 6 moles of H_2O

So, 0.3035 moles of C_5H_{12} react to give 0.3035\times 6=1.821 moles of H_2O

Now we have to calculate the mass of H_2O.

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g

Therefore, the mass of water produced will be 32.78 grams.

3 0
3 years ago
Please help me ASAP
blondinia [14]

Answer:

weak acid

Explanation:

pH scale is from 0 to 14

pH =7 is for water which is neutral.  it is neither acidic or basic as the hydrogen ion concentration is equal to hydroxyl ion concentration.

Lesser the pH value than 7 greater the acidic nature. And greater the pH value  than 7 more the basic nature.

Given pH=3-7 So the indicated interval represents weakly acidic.

4 0
3 years ago
Mechanical twinning occurs in metals having which type(s) of crystal structure(s)?
kari74 [83]
Mechanical twinning occurs in metals having body center cubic and hexagonal closed packed structures. Twinning is said to occur when a portion of a crystal takes up an orientation that is related to the orientation of the untwinned lattice in a definite symmetrical manner. 
5 0
3 years ago
What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen? (5 points)
konstantin123 [22]
C3 H4 N1 ~~that’s what I think
8 0
3 years ago
A small portion of a crystal lattice is sketched below. What is the name of the unit cell of this lattice? Your answer must be a
Nikolay [14]

This is an incomplete question, the given sketch is shown below.

Answer : The name of given unit cell is, FCC (face-centered cubic unit cell)

Explanation :

Unit cell : It is defined as the smallest 3-dimensional portion of a complete space lattice which when repeated over the and again in different directions produces the complete space lattice.

There are three types of unit cell.

  • SCC (simple-centered cubic unit cell)
  • BCC (body-centered cubic unit cell)
  • FCC (face-centered cubic unit cell)

In SCC, the atoms are arranged at the corners.

Z=\frac{1}{8}\times 8=1

The number of atoms of unit cell = Z = 1

In BCC, the atoms are arranged at the corners and the body center.

Z=\frac{1}{8}\times 8+1=2

The number of atoms of unit cell = Z = 2

The given unit cell is, FCC because the atoms are arranged at the corners and the center of the 6 faces.

Z=\frac{1}{8}\times 8+\frac{1}{2}\times 6=4

The number of atoms of unit cell = Z = 4

Thus, the name of given unit cell is, FCC (face-centered cubic unit cell)

7 0
3 years ago
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