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UNO [17]
3 years ago
8

what is the percent yield of NH3 when 15.0 grams of nitrogen gas react with an excess of hydrogen gas to produce 15.4 grams of N

H3?
Chemistry
1 answer:
Vlad [161]3 years ago
8 0

Answer:

84.6%

Explanation:

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Please help asap. will give brainliest to correct answer
Usimov [2.4K]
The answer is 232 plus 450
7 0
3 years ago
Why is a thermos considered a (mostly) closed system? Question 3 options: different types of liquids stay hot thermoses come in
cestrela7 [59]

Answer:

Different types of hot or cold items can be stored in a thermos and power cannot enter or exit the system when the thermos lid is tightly closed

Explanation:

Closed systems are those that do not interact or do not exchange energy with the environment that surrounds them, that is why internal temperatures and conditions are maintained.

The human body is an open system, that is, it would be the opposite of the thermos since we constantly exchange energy with the environment through sweating, emission of gases, urine, feces, and the ingestion of food.

Thermoses are systems specially created to maintain a medium, it will be maintained if its lid is hermetically closed to prevent heat leakage or entry in situations of cold fluids.

4 0
3 years ago
Use the Nernst equation to calculate the corresponding voltage if the
spayn [35]

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8 0
2 years ago
Serine has pka1 = 2.21 and pka2 = 9.15. use the henderson-hasselbalch equation to calculate the ratio neutral form/protonated fo
malfutka [58]
Calculate the ratio by using Henderson-Hasselbalch equation:

pH = pKa + log [neutral form] / Protonated form

3.05 = 2.21 + log [neutral form] / [Protonated form]

3.05 - 2.21 = log [neutral form] / [Protonated form]

0.84 = log [neutral form] / [Protonated form]

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8 0
3 years ago
How much heat does it take to melt 5.0g solid copper?
Leya [2.2K]

Answer:

Q=1.04kJ

Explanation:

Hello,

In this case, for latent heat (phase change) we need to consider the enthalpy associated with the involved process, here, melting or fusion; thus, the enthalpy of fusion of copper is 13.2 kJ/mol, therefore, the heat is computed as:

Q=m\Delta H_{fus}

Nevertheless, since the given enthalpy is per mole of copper, we need to use its atomic mass to perform the correct calculation as follows:

Q=5.0g*\frac{1mol}{63.54}* 13.2\frac{kJ}{mol}\\ \\Q=1.04kJ

Which is positive as it needs to be supplied to the system.

Best regards.

5 0
3 years ago
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