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kobusy [5.1K]
2 years ago
13

Ravi’s grandmother is suffering from diabetes. Her doctor advised her to take lassi with less fat content. Which of the followin

g methods would be most appropriate for Ravi to prepare it? OPTIONS: a. Filtration b. Decantation c. Churning d. Sedimentation
Chemistry
1 answer:
bezimeni [28]2 years ago
3 0

Answer:

Explanation:

Hello friend

The answer is Churning.

Hope this helps

plz mark as brainliest!!!!!!

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The equilibrium constant k for the synthesis of ammonia is 6.8x105 at 298 k. what will k be for the reaction at 375 k?
spayn [35]
Answer is: K <span>be for the reaction at 375 K is 326.
</span>Chemical reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g); ΔH = -92,22 kJ/mol.
T₁<span><span> = 298 K
</span>T</span>₂<span><span> = 375 K
</span><span>Δ<span>H = -92,22 kJ/mol = -92220 J/mol.
R = 8,314 J/K</span></span></span>·mol.<span>
K</span>₁ = 6,8·10⁵.<span>
K</span>₂ = ?The van’t Hoff equation: ln(K₂/K₁) = -ΔH/R(1/T₂ - 1/T₁).
ln(K₂/6,8·10⁵) = 92220 J/mol / 8,314 J/K·mol (1/375K - 1/298K).
ln(K₂/6,8·10⁵) = 11092,13 · (0,00266 - 0,00335).
ln(K₂/6,8·10⁵) = -7,64.
K₂/680000= 0,00048
K₂ = 326,4.
6 0
3 years ago
Read 2 more answers
An astronomer studying planets outside our solar system has analyzed the atmospheres of four planets. Which of these planets’ at
Nata [24]

Answer: Planet A: 76% Nitrogen, 23% Oxygen, 1% Other

Explanation: Hope this helps!

3 0
2 years ago
A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant
Firlakuza [10]

Answer:

-3.28 × 10⁴ J

Explanation:

Step 1: Given data

  • Pressure exerted (P): 27.0 atm
  • Initial volume (Vi): 88.0 L
  • Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

5 0
3 years ago
A gas with a volume of 4.0L at a pressure of 205 kPa is allowed to expand to a volume of 12000 mL. What is the pressure in atmos
Leni [432]

Answer: The pressure in atmospheres is 0.674 in the container if the temperature remains constant.

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2  

where,

P_1 = initial pressure of gas  = 205 kPa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas  = 4.0 L

V_2 = final volume of gas = 12000 ml = 12 L    (1L=1000ml)  

205\times 4.0=P_2\times 12  

P_2=68.3kPa=0.674atm        (1kPa=0.0098atm)

Therefore, the pressure in atmospheres is 0.674 in the container if the temperature remains constant.

8 0
3 years ago
Salts usually have a low melting point
Svetradugi [14.3K]
Yes they do if that was your question
8 0
3 years ago
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