C. 4 decorated cupcakes.
Because 12 divided by 3 = 4, so you can have 4 cupcakes each with 3 cherries
Answer:
Washing Clothes & Dissolving Sugar
Explanation:
Think about each application:
1) Washing clothes: You kind of need water to do this, or not much washing can be done.
2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids.
3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.
4) Carving a sculpture: You would use solid tool and a sold sculpture.
5) Dissolving sugar: You need a liquid to dissolve sugar!
6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids.
7) A gear for a machine is a solid!
Answer:
Melting: solid liquid, Freezing: liquid to solid, Evaporation: liquid to gas.
Explanation:
mark me the brainliest
Answer:
E
Explanation:
To know what will happen, we need to know
the total number of electrons the element have.
This can be calculated by adding all the electrons together
That would be 2 + 2 + 6 + 2 + 4 = 16
This shows that the element is sulphur.
Now using the KLMN electronic configuration, sulphur has the shells 2,8,6 meaning there are 2 extra electrons needed for octet configuration to be achieved.
This makes option E the correct answer to the question
HOPE YOU UNDERSTAND. PLEASE MARK IT AS BRAINLIEST
Answer:
A (3,5), B (1,7) ,C(-1,-3),D(1,-5)
Explanation:
M[1,1]= [Diagonals bisect each other]
![[ \frac{x_{1} + x_{2}}{2} , \frac{y_{1} + y_{2}}{2}]\\(\frac{3+x_{2} }{2} , \frac{5+y_{2} }{2})\\\frac{3+x_{2} }{2}=1 , \frac{5+y_{2} }{2}=1\\3 + x_{2} = 2 , 5 + y_{2} = 2\\x_{2} = -1 , y_{2} = -3\\\\](https://tex.z-dn.net/?f=%5B%20%5Cfrac%7Bx_%7B1%7D%20%2B%20x_%7B2%7D%7D%7B2%7D%20%2C%20%5Cfrac%7By_%7B1%7D%20%2B%20y_%7B2%7D%7D%7B2%7D%5D%5C%5C%28%5Cfrac%7B3%2Bx_%7B2%7D%20%7D%7B2%7D%20%2C%20%5Cfrac%7B5%2By_%7B2%7D%20%7D%7B2%7D%29%5C%5C%5Cfrac%7B3%2Bx_%7B2%7D%20%7D%7B2%7D%3D1%20%2C%20%5Cfrac%7B5%2By_%7B2%7D%20%7D%7B2%7D%3D1%5C%5C3%20%2B%20x_%7B2%7D%20%3D%202%20%20%2C%20%205%20%2B%20y_%7B2%7D%20%3D%202%5C%5Cx_%7B2%7D%20%3D%20-1%20%20%20%2C%20%20y_%7B2%7D%20%3D%20-3%5C%5C%5C%5C)
C(-1,-3)
M[1,1]= [Diagonals bisect each other]
![[\frac{x+1}{2} , \frac{y+7}{2}]\\\frac{x+1}{2}=1 , \frac{y+7}{2}=1\\x+1=2 , y+7=2\\x=1, y=-5](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bx%2B1%7D%7B2%7D%20%2C%20%5Cfrac%7By%2B7%7D%7B2%7D%5D%5C%5C%5Cfrac%7Bx%2B1%7D%7B2%7D%3D1%20%20%2C%20%20%5Cfrac%7By%2B7%7D%7B2%7D%3D1%5C%5Cx%2B1%3D2%20%20%2C%20%20y%2B7%3D2%5C%5Cx%3D1%2C%20y%3D-5)
D(1,-5)
hence,
A (3,5), B (1,7) ,C(-1,-3),D(1,-5)
