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Alexeev081 [22]
3 years ago
13

In animal cells, DNA is organized in the _______.

Chemistry
2 answers:
Luda [366]3 years ago
5 0
The answer is: Nucleus (same as in plant cells)
Ksju [112]3 years ago
5 0
The answer is in the nucleus.
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Which of the following oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation
Murljashka [212]

Answer: Option (B) is the correct answer.

Explanation:

When a fatty acid contains high number of double bonds then its unsaturation will also be high and hence, it will consume greater number of equivalents of hydrogen.

In corn oil, there are no unsaturated sites are present.

In olive oil, there is one unsaturated site with majority of oleic acid. In olive oil, there are more than 70% of total unsaturated oils.

In lard oil, there are around 60% of unsaturated oils.

In herring oil, there are highest number of saturated fatty acids and lowest polyunsaturated acids.

Thus, we can conclude that out of the given options, olive oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation.

5 0
3 years ago
What are the characteristics of a substance in the liquid state?
lidiya [134]
<span>Made up of particles packed relatively close together, having an indefinite shape but a definite volume</span>
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3 years ago
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Methane burns in oxygen to produce carbon dioxide and water. Which of the following represents
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Answer:

A

Explanation:

CH4+O2-CO2+ H20

that mean methane has burn in oxygen to produce CO2

8 0
3 years ago
List 3 Metals in the periodic table.
musickatia [10]
Chromium , silver, zinc...
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2 years ago
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A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
3 years ago
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