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liberstina [14]
3 years ago
12

Despite their name, standing waves actually do cause the medium to move

Physics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

true

Explanation:

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sammy [17]

Hi, what is it you need help with?

8 0
2 years ago
A circular loop of wire with a radius of 12.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
kirza4 [7]

Answer:

The average induced emf is 29.06 V

Explanation:

Given;

radius of the circular loop, r = 12.0 cm = 0.12 m

magnetic field strength, B =  1.8 T

time interval = 2.8 ms = 0.0028 s

Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

e.m.f =\frac{BA}{t}

where;

B is magnetic field

A is area

t is time

substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

e.m.f =\frac{1.8 *0.0452}{0.0028} = 29.06 \ V

Therefore, the average induced emf is 29.06 V

5 0
3 years ago
What provided evidence for the revolution of earth around the sun?.
Alika [10]

Explanation:

there are many things. I am not sure what your teacher told you.

one of the first strange observations leading to this conclusion was the "loop-di-loop" in the track of Mars. because of the different orbits of Earth and Mars, sometimes one (particularly Earth as the faster one) swings around the sun in relation to the other, and with that first moves away and suddenly moves closer again, making the track of Mars appear on Earth as if it would make a loop in the sky.

6 0
3 years ago
A student constructed a simple electric circuit where two light bulbs were connected in parallel. The circuit power source was a
Natasha2012 [34]

Answer:

RT =  17 ohms

Explanation:

For two parallel resistances in a circuit the combined resistance is given by:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}\\\\\frac{1}{R_T}=\frac{R_2+R_1}{R_1R_2}\\\\R_T=\frac{R_1R_2}{R_1+R_2}

R1 = 25 ohms

R2 = 50 ohms

You replace the values of R1 and R2 in the formula for RT:

R_T=\frac{(25)(50)}{25+50}ohms=16.66\ ohms \approx 17\ ohms

hence, the combined resitances is 17 ohms

5 0
4 years ago
A wheel of diameter 138 cm has an axle of diameter 9 cm. A force 120 N is exerted along the rim of the wheel. What force should
fiasKO [112]

Answer:

Explanation:

The axle is the shaft that the wheel is mounted on

The force applied to the rim of the wheel produces a torque = force * distance = 120N * 1.38m (Nm)

The torque applied to the axle must balance this, therefore the force = 120N * 1.38/0.09

=1840N

3 0
3 years ago
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