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xeze [42]
3 years ago
8

A point charge of 4.0 µC is placed at a distance of 0.10 m from a hard rubber rod with an electric field of 1.0 × 103 . What is

the electric potential energy of the point charge?
× 10–4 J

What is the electric potential energy of the point charge at 1.3 m?


× 10–3 J
Physics
2 answers:
Afina-wow [57]3 years ago
4 0

The electric potential energy of the point charge is 4.

the electric potential energy of the point charge at 1.3 m is 5.2.

Juliette [100K]3 years ago
4 0

Answer:

Part 1)

U = 4 \times 10^{-4} J

Part 2)

U = 5.2 \times 10^{-3} J

Explanation:

Electric field due to rubber rod is given by

E = 1.0 \times 10^3 N/c

now we also know that

V = E. r

V = (1.0 \times 10^3)(0.10)

V = 1.0 \times 10^2

now potential energy is given as

U = qV

U = (4 \mu C)(1.0 \times 10^2)

U = 4 \times 10^{-4} J

Similarly the electric potential at distance r = 1.3 m

so we have

V = (1.0 \times 10^3)(1.3)

V = 1.3 \times 10^3 Volts

now potential energy is given as

U = (4\mu C)(1.3 \times 10^3)

U = 5.2 \times 10^{-3} J

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