Question

You illuminate a slit with a width of 0.0549 mm with a light of wavelength 735 nm and observe the resulting diffraction pattern on a screen that is situated 2.85 m from the slit. What is the width, in centimeters, of the pattern's central maximum?

Answer 1

Answer:

Explanation:

Given

slit width $d=0.0549\ mm$

wavelength of light $\lambda =735\ nm$

Screen is placed at a distance of $D=2.85\ m$

The angle for the first minima is given by

$\sin \theta _1=\frac{m\lambda }{d}$

for m=1

$\sin \theta _1=\frac{1\times 735\times 10^{-9}}{0.0549\times 10^{-3}}$

$\sin \theta _1=0.0133$

and one half of central maxima is given by

$Y=D\sin \theta _1$

$Y=2.85\times 0.0133$

$Y=0.0381\ m$

Width of central maxima $=2Y$

$Width=0.0762\ m\approx 7.62\ cm$