Question

What is the expected freezing-point depression for a solution that contains 2.0 mol of KCI

Answer 1

Answer:

a. -7.44 °C

Explanation:

Hello there!

In this case, since the freezing point depression formula is:

$\Delta T_f=-i*m*Kf$

Thus, since the Van't Hoff's factor is 2 for KCl as it ionizes in K⁺ and Cl⁻, the molarity is 2.0 m (2.0mol/1.0kg) and the freezing point depression constant is 1.86 °C/m, we calculate the freezing point depression as follows:

$\Delta T_f=-2*2.0m*1.86\°C /m\\\\\Delta T_f=-7.44\°C$

Therefore, the answer is a. -7.44 °C.

Regards!