All categories

3 years ago

5. Calculate the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L.

Chemistry

1 answer:

Kazeer [188]3 years ago

5 0

Answer: 195.3 K

Explanation: Use Charles Law to get T2

Charles Law V1 / T1 = V2 / T2

Derive the equation to find T2

T2 = V2T1 / V1

Convert temperature into K

T1 = 20.0 °C + 273 = 293 K

Substitute the values:

4.00 L x 293 K / 6.00 L = 195. 3 K

You might be interested in

For the equilibrium

sleet_krkn [62]

Answer:

$\large \boxed{\text{0.091 atm }}$

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

Kc = 8.50 × 10⁻³

n(IBr) = 0.0600 mol

V = 1.0 L

1. Calculate [IBr]

$\text{[IBr]} = \dfrac{\text{0.0600 mol}}{\text{1.0 L}} = \text{0.0600 mol/L}$

2. Set up an ICE table.

$\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} & & \\0 & & 0 & &0.0600 & & \\+x & & +x & &- 2x & & \\x & & x & & 0.0600 - 2x & & \\\end{array}$

3. Calculate [I₂]

$\begin{array}{rcl}K_{\text{c}}&=&\dfrac{\text{[IBr]}^{2}} {\text{[I$_{2}$][Br]$_{2}$}}\\\\8.50 \times 10^{-2}&=&{\dfrac{(0.0600 - 2x)^{2}}{x^{2}}}& &\\\\0.2915x & = &{\dfrac{0.0600 - 2x}{x}}& &\\\\0.2915x & = &0.0600 - 2x\\\\2.2915x & = & 0.0600\\x & = & \textbf{0.026 18 mol/L}\\\end{array}\\$

4. Convert the temperature to kelvins

T = (150 + 273.15) K = 423.15 K

5. Calculate p(I₂)

$\begin{array}{rcl}\\pV & = & nRT\\p & = & cRT\\p & = & \text{0.026 18 mol} \cdot \text{L}^{-1}\times \text{0.082 06 L} \cdot \text{atm} \cdot \text{K}^{-1} \text{mol}^{-1} \times \text{423.15 K}\\& = & \textbf{0.91 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.91 atm}}$}$

6 0

3 years ago

when 1 mol of glucose is burned, 2802.5kj of energy is released. calculate rhe quantity of energy released to a person by eating

tester [92]

77.78 kJ of energy is released when 1 mol of glucose is burned, 2802.5 kJ of energy is released.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Calculate the moles of 5.00g of glucose.

Given mass = 5.00g

The molar mass of glucose = 180.156 g/mol

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{5.00g}{180.156 g/mol}$

Moles =0.02775372455

The quantity of energy released to a person by eating 5.00g of glucose in a candy.

0.02775372455 x 2802.5 kJ

77.77981305 kJ =77.78 kJ

Hence, 777.78 kJ of energy is released.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

8 0

2 years ago

Why do we have to pay if its just learning

Oxana [17]

Answer:

what are we paying for?

Explanation:

8 0

3 years ago

Solid iron metal reacts with solid sulfur at room temperature to produce solid iron (ll) sulfide? Express as a chemical equation

kupik [55]

Answer:Fe+S=FeS

Hope this helps

5 0

2 years ago

How to prepare super saturated solution of copper sulphate ? Explain the experiment

expeople1 [14]

Explanation:

Monitor the temperature of the water with the thermometer. Stop heating the water once it nears the boiling point of 100 degrees Celsius. Add copper(II) sulfate and stir until the heated solution is saturated. When the solution is saturated, copper(II) sulfate will not dissolve anymore

6 0

2 years ago