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-Dominant- [34]
3 years ago
8

5. Calculate the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L.

Chemistry
1 answer:
Kazeer [188]3 years ago
5 0

Answer: 195.3 K

Explanation: Use Charles Law to get T2

Charles Law V1 / T1 = V2 / T2

Derive the equation to find T2

T2 = V2T1 / V1

Convert temperature into K

T1 = 20.0 °C + 273 = 293 K

Substitute the values:

4.00 L x 293 K / 6.00 L = 195. 3 K

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Answer:  [H^+] of 0.056 M HF solution is 8.96\times 10^{-5}

Explanation:

HF\rightarrow H^+F^-

 cM              0             0

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So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.056 M and \alpha = ?

K_a=1.45\times 10^{-7}

Putting in the values we get:

1.45\times 10^{-7}=\frac{(0.056\times \alpha)^2}{(0.056-0.056\times \alpha)}

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Thus [H^+] of 0.056 M HF solution is 8.96\times 10^{-5}

8 0
3 years ago
Which pair of elements is most likely to chemically combine and form ionic bonds, chlorine and chlorine or lithium and chlorine,
olya-2409 [2.1K]
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7 0
4 years ago
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4 years ago
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