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Brut [27]
2 years ago
8

Fill out the information below for the following graph of a quadratic function. Please Help!!

Mathematics
1 answer:
Inessa [10]2 years ago
6 0

Answer:

Please refer to the images attached below.

Step-by-step explanation:

Quadratic Functions are functions of degree 2. The graph of any quadratic function is a parabola that has a vertex and axis of symmetry.

Some Properties of Graph Translations

1. y=a(x-h)^2+ky=a(x−h)

2

+k

This means that the new function is translated h units to the right and k units going up.

2. y=a(x-h)^2-ky=a(x−h)

2

−k

This means that the new function is translated h units to the right and k units going down.

3. y=a(x+h)^2+ky=a(x+h)

2

+k

This means that the new function is translated h units to the left and k units going up.

4. y=a(x+h)^2-ky=a(x+h)

2

−k

This means that the new function is translated h units to the left and k units going down.

First, let's graph the function y=3x^2+3y=3x

2

+3 . The vertex is at the point (0,3)(0,3) . Please refer to Figure 1 below.

Now, start from the vertex of the first function, (0,3)(0,3) , as you notice that the function y=3(x-3)^2+1y=3(x−3)

2

+1 is 3 units translation to right and one unit translation going up. This means that the new vertex is the point (3,1)(3,1) .Please refer to Figure 2.

For the function, y=3(x+3)^2-1y=3(x+3)

2

−1 , start from the vertex of the first function, (0,3)(0,3) , then make a translation of 3 units to the left and a translation of 1 unit down. This gives us a new vertex of (-1, -3)(−1,−3) . Please refer to Figure 3.

#LetsStudy

To learn more about quadratic functions, go to

https://brainly.ph/question/2436149

https://brainly.ph/question/4568410

https://brainly.ph/question/5982152

Step-by-step explanation:

<em>FOLLOW</em><em> </em><em>ME </em><em>OKAY </em><em />

<em>I </em><em>WILL</em><em> FOLLOW</em><em> </em><em>YOU</em><em> </em><em>BACK</em><em> </em><em />

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Answer:

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Step-by-step explanation:

Previous concepts

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Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

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