Test 2
In Test 1, the worm is observed in its natural state, making that the control group.
Answer:
(B)
Explanation:
The colligative properties of any given solution are properties that are dependent on the concentration of the molecules or ions of the solute in the solution, and not on the type or identity of that solute. Examples of colligative properties:
1. Lowering of vapour pressure
2. Elevation of boiling point,
3. Depression of freezing point and
4. Osmotic pressure
(A) is not a colligative property because the scenario talks about the freezing point of a pure solvent and not a solution.
(C) is not a colligative property because the solutions being compared are completely different (the solutes are different).
(B) is a colligative property because it talks about the freezing point of a solution
Answer:
The rise in sea level it will be of 0.08 Km.
Explanation:
The relation between volume (V) and mass (m) is density (δ):
δ = m / V
First, knowing the volume of ice in the Antarctic and the density of the ice, it is possible to calculate the mass of ice that will melt:
m = δ.V =
The mass of ice is 2.77x1022 so, the mass of water entering the oceans is the same.
Second, knowing the mass of water and the density of water, it is possible to calculate the volume of water entering the oceans:
V = m / δ =
Third, assuming that the oceans of the world cover an area, A, of about 3.62 x 108 km2 and that the increase in volume of the oceans can be calculated as A x h:
h = V/A =