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vlabodo [156]
3 years ago
7

Why are state symbols used in chemical equations

Chemistry
2 answers:
DedPeter [7]3 years ago
4 0

Answer:

state symbol meaning

[s] solid

liquid

gas

aq] aqueous dissolved in water

Explanation:

often chemical equations are written showing the state that each substance is in. the [s] sign means that the compound is a sold. the l sign means the substance is a liquid. the aq sign stands for aqueous in water and means the compound is dissolved in water

thank me later.

galina1969 [7]3 years ago
4 0
State symbols are used in chemical equations bc they identify what phase the substances are in.
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Sedbober [7]

Answer:

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7 0
3 years ago
Determine whether or not baco3 will be more soluble in acidic solution than in pure water.
Volgvan
Barium carbonate (BaCO₃) <span>will be more soluble in acidic solution than in pure water, because Ksp (solubility constant) in water for this salt is very low.
In acid (for example hydrochloric acid) barium carbonate dissolves more because it forms weak electrolyte carbonic acid:
BaCO</span>₃(s) + 2HCl(aq) → BaCl₂(aq) + H₂CO₃(aq).
4 0
3 years ago
This question involves two calculations. The answer to the first part will be
ozzi

Answer :

(a) The mass of Al_2O_3 produced is, 15.2 grams.

(b) The percent yield of the reaction is, 72.5 %

Explanation :

Part (a) :

Given,

Mass of Al = 85.1 g

Molar mass of Al = 27 g/mol

First we have to calculate the moles of Al

\text{Moles of }Al=\frac{\text{Given mass }Al}{\text{Molar mass }Al}=\frac{85.1g}{27g/mol}=3.15mol

Now we have to calculate the moles of Al_2O_3

The balanced chemical equation is:

4Al+3O_2\rightarrow 2Al_2O_3

From the reaction, we conclude that

As, 4 moles of Al react to give 2 moles of Al_2O_3

So, 3.15 moles of Al react to give \frac{2}{4}\times 3.15=1.58 mole of Al_2O_3

Now we have to calculate the mass of Al_2O_3

\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3

Molar mass of Al_2O_3 = 102 g/mole

\text{ Mass of }Al_2O_3=(1.58moles)\times (102g/mole)=161.2g

Therefore, the mass of Al_2O_3 produced is, 161.2 grams.

Part (b) :

Now we have to calculate the percent yield of the reaction.

\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield = 116.9 g

Theoretical yield = 161.2 g

Now put all the given values in this formula, we get:

\text{Percent yield}=\frac{116.9g}{161.2g}\times 100=72.5\%

Therefore, the percent yield of the reaction is, 72.5 %

8 0
3 years ago
2+2= ? 3+3=? 2x2? 5867 cats + 800 dogs?
sukhopar [10]

Answer:

4

9

4

6667 animals

Explanation:

4 0
2 years ago
A 90.00 mL solution of NaCl and ethyl alcohol has 7.83 g of salt dissolved in the alcohol. Calculate the molar concentration of
nalin [4]
The  molar  concentration  of the solution  is calculated as  follows

find the moles of NaCl used  to  make the solution

moles =  mass/molar  mass
mass =7.83  g
molar  mass =58.5  g/mol
moles = 7.83 g/ 58.5 g/mol = 0.134 moles

molarity (  concentration  in mol/l) =  number  of moles/volume  in  liters

volume  in liters =  90ml/1000 =0.09  liters

molarity  is  therefore = 0.134  moles/0.09 L =1.49   M


8 0
3 years ago
Read 2 more answers
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