Answer:
1.00 × 10¹⁸
Explanation:
1. Calculate the <em>energy of one photon</em>
The formula for the energy of a photon is
<em>E</em> = <em>hc</em>/λ
<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹
λ = 477 nm = 477 × 10⁻⁹ m Insert the values
<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)
<em>E</em> = 4.165× 10⁻¹⁹ J
2. Calculate the <em>number of photons</em>
Divide the total energy by the energy of one photon.
No. of photons = 0.418 × 1/4.165 × 10⁻¹⁹
No. of photons = 1.00 × 10¹⁸
H2SO4 (1) H20 (g) + SO3 (g)
Answer:
10 L
Explanation:
The only variables are pressure and volume, so we can use Boyle's Law:
p1V1 = p2V2
Data:
p1 = 125 atm; V1 = 4.0 L
p2 = 50 atm; V2 = ?
Calculation:
125 × 4.0 = 50V2
500 = 50 V2
V2 = 500/50 = 10 L
The new volume will be 10 L.
