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Vanyuwa [196]
3 years ago
9

Architects design roads. A. True B. False

Engineering
2 answers:
Hatshy [7]3 years ago
6 0
Answer:

B. it’s False
dalvyx [7]3 years ago
4 0
A. True

What kind of class is this
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A rigid insulated tank is divided into 2 equal compartments by a thin rigid partition. One of the compartments contains air, ass
Illusion [34]
Https://www.slader.com/discussion/question/an-insulated-rigid-tank-is-divided-into-two-equal-parts-by-a-partition-initially-one-part-contains-4/



there will be the answer

6 0
3 years ago
a cantilever beam 1.5m long has a square box cross section with the outer width and height being 100mm and a wall thickness of 8
djverab [1.8K]

Answer:

a) 159.07 MPa

b) 10.45 MPa

c) 79.535 MPa

Explanation:

Given data :

length of cantilever beam = 1.5m

outer width and height = 100 mm

wall thickness = 8mm

uniform load carried by beam  along entire length= 6.5 kN/m

concentrated force at free end = 4kN

first we  determine these values :

Mmax = ( 6.5 *(1.5) * (1.5/2) + 4 * 1.5 ) = 13312.5 N.m

Vmax = ( 6.5 * (1.5) + 4 ) = 13750 N

A) determine max bending stress

б = \frac{MC}{I}  =  \frac{13312.5 ( 0.112)}{1/12(0.1^4-0.084^4)}  =  159.07 MPa

B) Determine max transverse shear stress

attached below

   ζ = 10.45 MPa

C) Determine max shear stress in the beam

This occurs at the top of the beam or at the centroidal axis

hence max stress in the beam =  159.07 / 2 = 79.535 MPa  

attached below is the remaining solution

6 0
3 years ago
Assume a factory releases a continuous flow of wastewater into a local stream, resulting in an in-stream carcinogen concentratio
AlladinOne [14]

Answer:

Calculate the individual residential lifetime cancer risk.  

Risk = Potential factor x CDI  …… (1)

Calculate the value of C  

C =  C_{o} * e^{-kt}

t = d / v

t = 150 miles / 2 mile per hrs.

t = 75 hrs

t = 75/24

t = 3.13 days

Substitute the obtained value in (2).

C = C_{o} * e^{-kt}

C = 0.72 x e^(-0.1*3.13)

C = 0.72 x 0.7313  

C = 0.526 mg/L

Substitute the obtained value in (1).

Risk = Potential factor x CDI

Risk = 0.30kg.d/mg x 0.526mg/L x 2L/d x 350day/365days

Risk = 0.3026

8 0
3 years ago
An uncovered swimming pool loses 1.0 inch of water off its 1,000 ft^2 surface each week due to evaporation. The heat of vaporiza
soldi70 [24.7K]

Answer:

The affirmation is true, the cover will be worth buying

Explanation:

The equation necessary to use is

E = m*cv,

Where

cv: the heat of vaporization.  

Finding the rate at which the water evaporates (m^3/week).  

The swimming pool loses water at 1 inch/week off its 1,000 ft^2

Than,

1000 ft² * 1 in/wk * 1 ft/12 in = 83.33 ft³/week

To obtains the rate of mass loss it is necessary to multiply it for the density of water

83.33 ft³/week * 62.4 lb/ft³ = 5200 lb/week

Knowing the vaporization heat it is possible to find the rate of heat which is leaving the swimming pool  

5200 lb/week * 1050 BTU/lb = 5460000 btu/week

Over a 15-week period, the pool loses 81.9 million BTU.  

Knowing the cost of energy to heat the pool is $10.00 per million btu

The price = $819

This way, the affirmation is true, the cover will be worth buying

3 0
3 years ago
An escalator in a shopping center is designed to move 50 people, 75 kg each, at a constant speed of 0.6 m/s at 45° slope. Determ
kramer

Answer:

\dot E = 15602.842\,W

Explanation:

By an adequate application of the Principle of Energy Conservation, the escalator need energy to elevate from to the bottom to the top. Hence:

E = m_{total}\cdot g \cdot y

An expression for power needed is found by deriving the equation with respect to time:

\dot E = m_{total}\cdot g \cdot v_{y}

The minimum power is found by substituting known inputs:

\dot E = (50)\cdot (75\,kg) \cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.6\,\frac{m}{s} )\cdot \sin 45^{\textdegree}

\dot E = 15602.842\,W

6 0
3 years ago
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