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olchik [2.2K]
4 years ago
5

Two small balls A and B with masses 2m and m respectively are released from rest at a height h above the ground. Neglecting air

resistance, which of the following statements are true when the two balls hit the ground?
(a) The kinetic energy of A is the same as the kinetic energy of B
(b) The kinetic energy of A is half the kinetic energy of B.
(c) The kinetic energy of A is twice the kinetic energy of B.
(d) The kinetic energy of A is four times the kinetic energy of B Explain your answer why.
What is the definition of General Plan Motion? What would be the effective methodology or approach to solve a rigid body kinematics problem?
Engineering
1 answer:
statuscvo [17]4 years ago
5 0

Answer:

The kinetic energy of A is twice the kinetic energy of B

Explanation:

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\o you sell them?” "Fivepence farthing for one—Twopence for two,” the Sheep replied. "Then two are cheaper than one?” Alice said
NemiM [27]

Answer:

unusual and strange

Explanation:

3 0
3 years ago
Technician A says that a lack of lubrication on the back of the disc brake pads can cause brake noise. Technician B says that pa
sweet-ann [11.9K]

Answer:

Technician A and B both are correct.

Explanation:

According to Technician A, we can stop noise by applying lubricant (Break friction).

According to Technician A, we can stop noise by set-up right position for break pad.

7 0
3 years ago
1. AC is safer for welders to use in hazardous spaces because currents are even, generate less spatter residue, and
igor_vitrenko [27]
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6 0
3 years ago
Suppose there are 76 packets entering a queue at the same time. Each packet is of size 5 MiB. The link transmission rate is 2.1
tia_tia [17]

Answer:

938.7 milliseconds

Explanation:

Since the transmission rate is in bits, we will need to convert the packet size to Bits.

1 bytes = 8 bits

1 MiB = 2^20 bytes = 8 × 2^20 bits

5 MiB = 5 × 8 × 2^20 bits.

The formula for queueing delay of <em>n-th</em> packet is :  (n - 1) × L/R

where L :  packet size = 5 × 8 × 2^20 bits, n: packet number = 48 and R : transmission rate =  2.1 Gbps = 2.1 × 10^9 bits per second.

Therefore queueing delay for 48th packet = ( (48-1) ×5 × 8 × 2^20)/2.1 × 10^9

queueing delay for 48th packet = (47 ×40× 2^20)/2.1 × 10^9

queueing delay for 48th packet = 0.938725181 seconds

queueing delay for 48th packet = 938.725181 milliseconds = 938.7 milliseconds

4 0
3 years ago
Explain the use of the Kanban system in a production line?
AURORKA [14]

Answer:

Kanban is a tool which are design to reduce the insignificant time in the production process. The main aim of Kanban system is to delivered the exactly requirement of the process.

Kanban comes from the Japanese word which means visual card. Kanban system maintain and improve the efficiency of production.

Its purpose is satisfied the requirement of customers and control the quality of the production.

7 0
3 years ago
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