Answer:
Explanation:
Given data:
initial construction co = 0.286 wt %
concentration at surface position cs = 0 wt %
carbon concentration cx = 0.215 wt%
time = 7 hr

for 0.225% carbon concentration following formula is used

where, erf stand for error function




from the table erf(Z) value = 0.751 lie between (z) = 0.80 and z = 0.85 so by inteerpolation we have z = 0.815
from given table



x = 0.002395 mm
Answer:
D=41.48 ft

Explanation:
Given that
y=0.5 x²
Vx= 2 t
We know that

At t= 0 ,x=0

At t= 3 s

![x=[t^2\left\right ]_0^3](https://tex.z-dn.net/?f=x%3D%5Bt%5E2%5Cleft%5Cright%20%5D_0%5E3)
x= 9 ft
When x= 9 ft then
y= 0.5 x 9² ft
y= 40.5 ft
So distance from origin is
x= 9 ft ,y= 40.5 ft

D=41.48 ft

Vx= 2 t

At t= 3 s , x= 9 ft
y=0.5 x²

y=0.5 x²


Given that








Answer:
Efficiency based on Otto cycle.
Effotto = 47.47%
Explanation:
Efficiency based on Otto cycle.
effotto = 1 – (V2 / V1)^γ-1
effotto = 1 – (1 / 5)^1.4 - 1
effotto = 47.47%
Answer:
Yes
Explanation:
Given Data
Temprature of source=750°c=1023k
Temprature of sink =0°c=273k
Work produced=3.3KW
Heat Rejected=4.4KW
Efficiency of heat engine(η)=
and
Heat Supplied 

η=
η=42.85%
Also the maximum efficiency of a heat engine operating between two different Tempratures i.e. Source & Sink
η=1-
η=1-
η=73.31%
Therefore our Engine Efficiency is less than the maximum efficiency hence the given claim is valid.