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Korolek [52]
3 years ago
10

How much 2.0 M phenylmagnesium chloride solution is needed if adding 2.9 mmol of Grignard reagent to a reaction? Your answer sho

uld be in mL and you should answer to the second decimal place. Do NOT include the unit label, answer only with a number.
Chemistry
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

1,45 mL

Explanation:

The Grignard reaction is a very important organometallic chemical reaction where the Grignard reagent ( alkyl, vinyl, or aryl-magnesium halides) acts as nucleophile in order to the formation of Carbon-Carbon bonds.

In the problem, the phenylmagnesium chloride is the grignard reagent. The volume of 2.0 M phenylmagnesium chloride solution you need to add 2.9 mmol is:

2,9 mmol × \frac{1mL}{2,0mM} = <em>1,45 mL</em>

<em></em>

I hope it helps!

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6. What is the atomic mass of Hafnium if out of every 200 atoms, 10 have mass 176.00 g/mol, 38 have mass
Zinaida [17]

Answer:

ttyhjj

Explanation:

4 0
3 years ago
Based on the diagram below, which would have the most inertia?
jeka94

Answer:

The sphere on the left has the most inertia because it has more mass.

Explanation:

Inertia is a property of matter of a substance.

According to Newton's first law of motion, a body continues to stay in the state of rest or constant velocity unless acted upon a external force.

The amount of inertia that an object possess is proportional to the mass of the object.

The sphere on the left is of 300 kg and that on the right is of 30 kg.

Clearly, the sphere on the left has more mass.

Therefore, the sphere on the left has the most inertia.

6 0
3 years ago
Read 2 more answers
How many atoms are there in 20.00 moles of calcium (Ca)?
laila [671]

Answer:

20 x (6.022 x 10^23) atoms in 20 moles of Calcium.

Explanation:

A mole contains 6.022 x 10^23 atoms, which is also known as Avogadro's number, and this number is same for each element. So, there are 20 x (6.022 x 10^23) atoms in 20 moles of Calcium.

7 0
3 years ago
Read 2 more answers
The initial volume of HCl was 1.25 ml and LiOH was 2.65 ml. The final volume of HCL was 13.60 ml and LiOH was 11.20 ml. If the L
Dennis_Churaev [7]
Q1)
This is a strong acid- strong base base reaction, balanced equation for the reaction is as follows;
LiOH + HCl ---> LiCl + H₂O
stoichiometry of acid to base is 1:1
volume of HCl used up - 13.60 - 1.25 = 12.35 mL
volume of LiOH used up - 11.20 - 2.65 = 8.55 mL
molarity of LiOH - 0.140 M
The number of LiOH moles reacted - \frac{0.140 mol/L*8.55mL}{1000mL} = 0.001197 mol
according to stoichiometry, number of LiOH moles = number of HCl moles
Therefore number of HCl moles reacted - 0.001197 mol
The number of  HCl moles in 12.35 mL - 0.001197 mol 
Then number of HCl moles in 1000 mL - \frac{0.001197*1000mL}{12.35mL}
Molarity of HCl - 0.0969 M

Q2)
Volume of HCl used - 12.35 mL
Volume of LiOH used - 8.55 mL
Molarity of HCl - 0.140 M
In 1 L solution of HCl there are 0.140 mol of HCl
Therefore number of HCl moles in 12.35 mL - \frac{0.140mol*12.35 mL}{1000mL}
Number of HCl moles reacted - 0.001729 mol 
since molar ratio of acid to base is 1:1
the number of LiOH moles that reacted - 0.001729 mol
Therefore number of moles in 8.55 mL - 0.001729
Then number of LiOH moles in 1000 mL - \frac{0.001729mol*1000mL}{8.55 mL}
molarity of LiOH - 0.202 M
5 0
3 years ago
A mixture of helium and nitrogen gases, in a 7.03 L flask at 17 °C, contains 0.738 grams of helium and 8.98 grams of nitrogen. T
Andrei [34K]

Answer:

The partial pressure of nitrogen in the flask is 1.08 atm and the total pressure in the flask is 1.70 atm.

Explanation:

We must use the Ideal Gas Law to solve this:

Pressure . volume = n . R . T

T = T° in K → T°C + 273

17°C + 273 = 290K

n = moles

In a mixture, n is the total moles (Sum of each mol, from each gas)

Moles = Mass / Molar mass

Moles He = 0.738 g /  4g/m = 0.184 moles

Moles N₂ = 8.98 g / 28g/m = 0.320 moles

0.184 m + 0.320m = 0.504 moles

P . 7.03L = 0.504m . 0.082L.atm/ mol.K . 290K

P = (0.504m . 0.082L.atm/ mol.K . 290K) /7.03L

P = 1.70 atm  - This is the total pressure.

To know the partial pressure of N₂ we can apply, the molar fraction:

Moles of N₂ / Total moles = Pressure N₂ / Total pressure

0.320m / 0.504m = Pressure N₂ / 1.70atm

(0.320m / 0.504m) . 1.70atm = Pressure N₂

1.08atm = Pressure N₂

8 0
4 years ago
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