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Aneli [31]
3 years ago
8

Wht kind of particles contribute to an overall heating effect on climate?​

Chemistry
2 answers:
MakcuM [25]3 years ago
6 0

Answer:

Aerosols like sulfur, nitrate, and organic carbon are formed in the atmosphere and cause global cooling. Thereby they contribute to mask parts of the human induced global warming. On the other hand, black carbon absorbs radiation and thereby has a warming effect on the earth's climate

Explanation:

google hope this helps you

Ivanshal [37]3 years ago
3 0

Answer: Aerosols like sulfur, nitrate, and organic carbon are formed in the atmosphere and cause global cooling. Thereby they contribute to mask parts of the human induced global warming. On the other hand, black carbon absorbs radiation and thereby has a warming effect on the earth's climate. -science daily

Explanation: please mark me brainiest. i need one to get a higher rank :/

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Can you guys help me with this one too
posledela
The tractor would have the most kinetic energy :D
3 0
2 years ago
In one sample of a compound of copper and oxygen, 3.12g of the compound contains 2.50g of copper and the remainder is oxygen. Ca
blsea [12.9K]

Answer:

% composition O = 19.9%

% composition Cu = 80.1%

Explanation:

Given data:

Total mass of compound = 3.12 g

Mass of copper = 2.50 g

Mass of oxygen = 3.12 - 2.50 = 0.62 g

% composition = ?

Solution:

Formula:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition Cu = (2.50 g / 3.12 g)×100

% composition Cu = 0.80 ×100

% composition Cu = 80.1%

For oxygen:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition O = (0.62 g / 3.12 g)×100

% composition O = 0.199 ×100

% composition O = 19.9%

5 0
2 years ago
A sample of nitrogen gas had a volume of 500. ml, a pressure in its closed container of 740 torr and a temperature 25 degrees c
Semenov [28]
Question:
              <span>A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?

Answer:

Data Given:
                   V</span>₁  =  500 mL

                   P₁  =  740 torr

                   T₁  =  25 °C + 273  =  298 K

                   V₂  =  ?

                   P₂  =  760 torr

                   T₂  =  50 °C + 273  =  323 K

Solution:
             Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,

                      P₁ V₁ / T₁  =  P₂ V₂ / T₂

Solving for V₂,

                      V₂  =  (P₁ V₁ T₂) ÷ (T₁ P₂)

Putting Values,
  
                      V₂  =  (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)

                      V₂  =  527.68 mL
7 0
3 years ago
What is true of all eukaryotic organisms?
Basile [38]

Answer:

They are multicelled

Explanation:

I just did a quiz on it UwU

4 0
2 years ago
This graph shows two curves pertaining to a hydrogen s orbital.
fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function  which is denoted by R_{nl}(r) shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as R^{2}_{nl}(r) shown in  blue  color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds  which has radial and angular nodes which will be represented by <em>'n'</em>.

It is observed that for any atomic orbital, the total number of nodes will be n-1  .


Considering the s orbital of the hydrogen, which has zero angular momentum  (l); (l=0), as it has zero angular nodes.  

Hence, there will be only radial nodes, which is

(n−1  =  total number of radial nodes in s orbitals)

According to the image, there are 4  radial nodes shown, so n  =  5  (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.


Answer 2) The radial nodes are observed in I'm seeing radial nodes at  

1.9a_{0},  6.4a_{0},13.9a_{0} and  27.0a_{0}.

where  a_{0} represents the  hydorgen bohr atomic radius =  0.0529177 nm


Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

3 0
2 years ago
Read 2 more answers
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