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Aneli [31]
3 years ago
8

Wht kind of particles contribute to an overall heating effect on climate?​

Chemistry
2 answers:
MakcuM [25]3 years ago
6 0

Answer:

Aerosols like sulfur, nitrate, and organic carbon are formed in the atmosphere and cause global cooling. Thereby they contribute to mask parts of the human induced global warming. On the other hand, black carbon absorbs radiation and thereby has a warming effect on the earth's climate

Explanation:

google hope this helps you

Ivanshal [37]3 years ago
3 0

Answer: Aerosols like sulfur, nitrate, and organic carbon are formed in the atmosphere and cause global cooling. Thereby they contribute to mask parts of the human induced global warming. On the other hand, black carbon absorbs radiation and thereby has a warming effect on the earth's climate. -science daily

Explanation: please mark me brainiest. i need one to get a higher rank :/

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Help me please i need the answer now<br>(nonsense report)​
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Quantitative

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3 0
3 years ago
Nitrogen dioxide is a red-brown gas that is responsible for the color of photochemical smog. What is the volume of 1 mol of nitr
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B ideal gas has a volume of 22.4
5 0
3 years ago
The molar mass of AI2CI6 is the mass of one mole of the compound. It is also which of the following?
Hunter-Best [27]

Answer:

Is their a picture with the question?

Explanation:

8 0
2 years ago
Un tanque de acetileno para una antorcha de soldadura de oxiacetileno proporciona 9340 L de gas acetileno, C2H2, a 0°C y 1 atm 2
Helen [10]

Answer:

3.33 tanques de O₂

Explanation:

Basados en la reacción:

2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

<em>2 moles de acetileno reaccionan con 5 moles de oxígeno produciendo 4 moles de dióxido de carbono y 2 moles de agua</em>

<em />

La ley de Avogadro dice que el volumen de un gas bajo temperatura y presión constantes es proporcional a las moles de este gas. Así, como 2 moles de acetileno reaccionan con 5 moles de oxígeno, los litros de O₂ necesarios para quemar 9340L de acetileno son:

9340 L C₂H₂ × (5 moles O₂ / 2 moles C₂H₂) = <em>23350L de O₂</em>

Si un tanque contiene 7x10³ L de O₂ serán necesarios:

23350L O₂ ₓ (1 tanque / 7x10³L) =<em> 3.33 tanques de O₂</em>

6 0
3 years ago
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