Question

A two digit number exceeds the sum of the digits of that number by 18. If the digits at the unit's place is double the digit in the ten's place, find the number

Answer 1

Answer:

The number is 24

Step-by-step explanation:

Let the two digits number be ab

In real terms, this is 10a + b

So, we have that the sum of the digits subtracted from 10a + b is 18

Mathematically, we have this as;

10a + b - (a + b) = 18

10a + b - a - b = 18

9a = 18

a = 18/9

a = 2

We are also told that the digit at the units place b is double the digit at the ten’s place a

That means b = 2a

b = 2 * 2 = 4