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2 years ago

What 3 things drive the pressure of a gas up

Chemistry

1 answer:

Sedaia [141]2 years ago

4 0

Answer:

<h3>Density of the Gas</h3>

Explanation:

More molecules mean more hits against the container walls. Increasing the number of particles means you have increased the density of the gas. This third factor is part of the ideal gas law, which explains how these three factors -- temperature, volume and density -- interact with each other.

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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

What is the most important reason to publish results as part of the scientific process?

svp [43]

<span>It allows other scientists to check findings</span> is the most important reason to publish results as part of the scientific process.

4 0

3 years ago

Read 2 more answers

PLEASE HELP WITH ALL

Gala2k [10]

Answer:

Question 1: D

Question 2: B C E F

Question 3: A

Question 4: A

Question 5: A

5 0

3 years ago

Read 2 more answers

When a student chemist transferred the metal to the calorimeter, some water splashed out of the calorimeter. will this technique

Natalka [10]

Answer:

It will be reported too low.

Explanation:

To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.

Qmetal + Qwater = 0

Qmetal = -Qwater

The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:

m_metal*s*ΔT_metal = - m_water *c*ΔT_water

s = -m_water *c*ΔT_water / m_metal*ΔT_metal

So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.

5 0

3 years ago

What are the products of the neutralization reaction between HCl and

liraira [26]

Answer:

opinion b

Explanation:

the product of neutralization reaction between hcl and CA(oh)2 is option b.

4 0

3 years ago