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2 years ago

What 3 things drive the pressure of a gas up

Chemistry

1 answer:

Sedaia [141]2 years ago

4 0

Answer:

<h3>Density of the Gas</h3>

Explanation:

More molecules mean more hits against the container walls. Increasing the number of particles means you have increased the density of the gas. This third factor is part of the ideal gas law, which explains how these three factors -- temperature, volume and density -- interact with each other.

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Which element gains two electrons to fill its outermost energy level?

laiz [17]

O magnesium Mg is the answer

4 0

2 years ago

A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO

Akimi4 [234]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=22.0g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_{1}H_{2}=CH_2$

4 0

3 years ago

I need to know the answers to this to make sure I am right

oee [108]

The answer is C............

3 0

3 years ago

Suppose 40.8g of copper(II) acetate is dissolved in 200.mL of a 0.70 M aqueous solution of sodium chromate.

Contact [7]

Answer:

0.42 M

Explanation:

The reaction that takes place is:

Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)

First we calculate the moles of Na₂CrO₄, using the given volume and concentration:

(200 mL = 0.200L)

0.70 M * 0.200 L = 0.14 moles Na₂CrO₄

Now we calculate the moles of Cu(CH₃COO)₂, using its molar mass:

40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂

Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂:

0.224 mol - 0.14 mol = 0.085 mol

Finally we calculate the resulting molarity of Cu⁺², from the excess cations remaining:

0.085 mol / 0.200 L = 0.42 M

4 0

3 years ago

How does the density of aluminum compare with the density of gold

rewona [7]

Gold has a very high density of about 19.32g/cm^3 while Aluminum has a low density of 2.7 gm/cm^3 which means gold can pack more amount of matter in a comparatively small space as compared to Aluminum.

3 0

3 years ago