<span>This can be solved using basic algebra. X equals the number of liters of 2% brine to add. Therefore we use this equation. 3 + 0.02x = 2.4 + 0.08x 0.6 = 0.6x x = 0..6/0.06 x = 10</span>
Copper ions, nitrate ions, and water is in the beaker
Answer: C(OCH2CH3)CHCClCH(CH)2
Explanation:
The structural formula for m-chlorophenyl ethyl ether is
C(OCH2CH3)CHCClCH(CH)2.
The structural formula shows the step-by-step linkages.
This substance most likely is an inert. It is a substance that is not chemically reactive. It does not change its chemical nature in a reaction. It does not <span>easily react with other chemicals. Most of the group 8 gases in the periodic table are classified as inert, due to their having full outer electron shells. </span>
Answer:
H^+(aq) + OH^-(aq) —> H2O(l)
Explanation:
We'll begin by writing the balanced equation for the reaction.
2HCl(aq) + Ca(OH)2(aq) —> CaCl2(aq) + 2H2O(l)
Ca(OH)2 is a strong base and will dissociates as follow:
Ca(OH)2(aq) —> Ca^2+(aq) + 2OH^-(aq)
HCl is a strong acid and will dissociates as follow:
HCl(aq) —> H^+(aq) + Cl^-(aq)
Thus, In solution a double displacement reaction occurs as shown below:
2H^+(aq) + 2Cl^-(aq) + Ca^2+(aq) + 2OH^-(aq) —> Ca^2+(aq) + 2Cl^-(aq) + 2H2O(l)
To get the net ionic equation, cancel out Ca^2+ and 2Cl^-
2H^+(aq) + 2OH^-(aq) —> 2H2O(l)
H^+(aq) + OH^-(aq) —> H2O(l)
