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noname [10]
3 years ago
13

A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid? The dens

ity of the liquid is grams/centimeter3.
Chemistry
2 answers:
Xelga [282]3 years ago
8 0

Density of liquid= \frac{mass of liquid}{volume of liquid}.

so, density of liquid= \frac{42 gm}{35 cm^{3} }= 1.2 gm/cm³.

Zinaida [17]3 years ago
5 0

Answer:

The density of the liquid is 1.2 g/cm^3

Explanation:

Density of the substance is defined as mass present in the unit volume of the substance.

Mass of the liquid ,M= 42 g

Volume of the liquid ,V= 35 cm^3

Density=\frac{Mass}{Volume}

Density=\frac{42 g}{35 cm^3}=1.2 g/cm^3

The density of the liquid is 1.2 g/cm^3

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Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because
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Answer:

0.3023 M

Explanation:

Let Picric acid = H_{picric}

So,  H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

The ICE table can be given as:

                          H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

Initial:                0.52                                               0                  0

Change:             - x                                                 + x                 + x

Equilibrium:      0.52 - x                                        + x                 + x

Given that;

acid dissociation constant  (K_a) = 0.42

K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}

0.42 = \frac{[x][x]}{0.52-x}}

0.42 = \frac{[x]^2}{0.52-x}}

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x²  + 0.42x - 0.2184 = 0                   -------------------- (quadratic equation)

Using the quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}    ;     ( where +/-  represent ± )

= \frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}

= \frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}

= \frac{-0.42+\sqrt {1.0496} }{2}     OR   \frac{-0.42-\sqrt {1.0496} }{2}

= \frac{-0.42+1.0245}{2}       OR    \frac{-0.42-1.0245}{2}

= \frac{0.6045}{2}                 OR    -\frac{1.4445}{2}

= 0.30225          OR     - 0.72225

So, we go by the +ve integer that says:

x =  0.30225

x = [ H_3}O^+ ] = [   Picric^- ] =  0.3023  M

∴  the value of  [H3O+] for an 0.52 M solution of picric acid  = 0.3023 M     (to 4 decimal places).

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Answer:

Yes

Explanation:

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