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anastassius [24]
3 years ago
9

In the image below, the dots represent gas molecules. When the wall separating the chambers is removed, how will the movement of

molecules change?

Chemistry
2 answers:
Grace [21]3 years ago
5 0
The correct answer is C.
vladimir1956 [14]3 years ago
5 0

Answer : The correct option is, (C)

Explanation :

Gas is one of the state of matter in which particles have a lot of spacing between them and are very far apart. The inter-molecular forces of attraction between the particles is the weakest.  

As we know that to maintain the equilibrium in the given chamber the molecules will flow from the right chamber to the left chamber and from left chamber to right chamber until the both chamber have equal number of molecules.

Hence, the correct option is, (c)

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Why is gold considered matter?
Yakvenalex [24]

Answer:

All matter is made up of substances called elements, which have specific chemical and physical properties and can't be broken down into other substances through ordinary chemical reactions. Gold, in this case, is an element so, therefore, it is considered matter.

Hope it helped :)

3 0
3 years ago
What features of earth's crust do convergent divergent and transform boundaries form
12345 [234]
Plate tectonics are the broken plates of earth that move around and form the different plate boundaries
8 0
3 years ago
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
What is the value of Avogadro's constant?​
diamong [38]

Answer:

6.02214154 x 1023

Explanation:

6 0
3 years ago
Can you pls answer this question cuz i don't know what is the answer on this..
Marysya12 [62]

Answer:

here's is ur answer in attachment

Explanation:

mark it brainliest if it helps you ❤️

3 0
3 years ago
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