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The rate of effusion of gas B is 728.32 m/s
<u>Explanation:</u>
Given:
Mass of A, m₁ = 46 g/mol
Rate of effusion of A, R₁ = 515 m/s
Mass of B, m₂ = 92 g/mol
Rate of effusion of B, R₂ = ?
We know:
Substituting the value we get:
Therefore, the rate of effusion of gas B is 728.32 m/s
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Answer:
pCl⁻ = 0.54
Explanation:
First we <u>calculate how many Cl⁻ moles are coming from each substance</u>, using the <em>given volumes and concentrations</em>:
- 0.12 M NaCl * 0.10 L = 0.012 mol NaCl = 0.012 mol Cl⁻
- 0.18 M MgCl₂ * 0.23 L = 0.0414 mol MgCl₂ = (0.0414 * 2) 0.0828 mol Cl⁻
The final volume of the mixture is = 0.10 L + 0.23 L = 0.33 L
Now we <u>calculate [Cl⁻]</u>, using the<em> total number of Cl⁻ moles and the final volume:</em>
- [Cl⁻] = (0.012 mol + 0.0828 mol) / 0.33 L = 0.29 M
Finally we <u>calculate the pCl⁻ of the resulting solution</u>: