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3 years ago

Were are you guys 123456789789456123456789123456789456

Chemistry

2 answers:

solniwko [45]3 years ago

5 0

What are u talking about lol

kolezko [41]3 years ago

4 0

Micheal told me in the closet I got some chicken I'm so sad

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For the reaction 2kclo3(s)→2kcl(s)+3o2(g) calculate how many grams of oxygen form when each quantity of reactant completely reac

barxatty [35]

First, we need to get the molar mass of:

KClO3 = 39.1 + 35.5 + 3*16 = 122.6 g/mol

KCl =39.1 + 35.5 = 74.6 g/mol

O2 = 16*2 = 32 g/mol

From the given equation we can see that:

every 2 moles of KClO3 gives 3 moles of O2

when mass = moles * molar mass

∴ the mass of KClO3 = (2mol of KClO3*122.6g/mol) = 245.2 g

and the mass of O2 then = 3 mol * 32g/mol = 96 g

so, 245.2 g of KClO3 gives 96 g of O2

A) 2.72 g of KClO3:

when 245.2 KClO3 gives → 96 g O2

2.72 g KClO3 gives → X

X = 2.72 g KClO3 * 96 g O2/245.2 KClO3

= 1.06 g of O2

B) 0.361 g KClO3:

when 245.2 g KClO3 gives → 96 g O2

0.361 g KClO3 gives → X

∴ X = 0.361g KClO3 * 96 g / 245.2 g

= 0.141 g of O2

C) 83.6 Kg KClO3:

when 245.2 g KClO3 gives → 96 g O2

83.6 Kg KClO3 gives → X

∴X = 83.6 Kg* 96 g O2 /245.2 g KClO3

= 32.7 Kg of O2

D) 22.4 mg of KClO3:

when 245.2 g KClO3 gives → 96 g O2

22.4 mg KClO3 gives → X

∴X = 22.4 mg * 96 g O2 / 245.2 g KClO3

= 8.8 mg of O2

7 0

4 years ago

What type of energy travels through space as waves?

RideAnS [48]

Shhdhdhdbdbrjfidjdnfnfbfbxuxfnmfmfksixjnfnfntjficjfjfj

7 0

3 years ago

Read 2 more answers

What is the empirical formula of propene CH3 CH2 CH2

kiruha [24]

Answer:

CH

Explanation:

Molecular formula of propene : C₃H₆

Take the HCF of carbon and hydrogen atoms :

3 = 3
6 = 2 x 3

Then, we can write the formula as :

3CH
This means there are 3 moles present

Empirical Formula :

Molecular Formula / No. of moles
C₃H₆ / 3
CH

The empirical formula of propene is CH

6 0

2 years ago

When an object is lifted 6 meters off the ground, it gains a certain amount of potential energy. If the same object is lifted 18

AlexFokin [52]

Answer:

The answer to your question is the letter C. three times as much

Explanation:

Data

First step = 6 m

Second step = 18 m

Potential energy is the energy stored that depends on its position.

Formula

Pe = mgh

m = mass; g = gravity; h = height

Potential energy of the first step

Pe1 = 6mg

Potential energy of the second step

Pe2 = 18mg

-Divide the Pe2 by the Pe1

Pe2/Pe1 = 18mg/6mg

= 3

7 0

3 years ago

Solid aluminum and gaseous oxygen read in a combination reaction to produce aluminum oxide. 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3

Kryger [21]

Answer:

4.7 g. Option 5 is the right one.

Explanation:

4Al(s) + 3O₂ (g) ⇄ 2Al₂O₃ (s)

We convert the mass of reactants to moles, in order to determine the limiting.

2.5 g Al / 26.98 g/mol → 0.092 moles of Al

2.5 g O₂ / 32g/mol → 0.078 moles of O₂

Ratio is 4:3. 4 moles of Al react with 3 moles of O₂

Then, 0.092 moles of O₂ would react with (0.092 . 3)/ 4 = 0.069 moles O₂

We have 0.078 moles of O₂ and we need 0.069 moles, the oxygen is the limiting in excess. Therefore the Al is the limiting reactant.

Ratio is 4:2. 4 moles of Al, can produce 2 moles of Al₂O₃

Then, 0.092 moles of Al would produce (0.092 .2) / 4 = 0.046 moles

If we convert the moles to mass, we find the anwer:

0.046 mol . 101.96 g/mol = 4.69 g

5 0

3 years ago