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coldgirl [10]
3 years ago
15

5 Facts about cell division

Chemistry
1 answer:
Kay [80]3 years ago
8 0
Search it up next time‍♀️

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What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K
vlada-n [284]

Answer:

=1.666 liters

Explanation:

1 mole of a has at standard temperature and pressure occupies a volume of 22.4 liters.

0.5 moles of nitrogen occupy a volume of (0.5 moles×22.4 dm³/mol)/ 1

=11.2 liters.

Standard pressure= 1 atmosphere (Atm)

Standard temperature = 273.15 Kelvin

According to Combined gas equation, P₁V₁/T₁=P₂V₂/T₂

Let us take the conditions under standard conditions as the reference, with the subscript 1 and the conditions under the 5L container to be scenario 2 with subscript 2.

Therefore P₂ =P₁V₁T₂/T₁V₂

Substituting for the values we get:

P₂= (1 atm× 11.2L ×203K)/ (273K×5L)

=1.666 atm

5 0
3 years ago
Provide the mass number of Fe, which has 29 neutrons
zmey [24]

Answer:

55.845 u

Explanation:

Fe, iron, has 29 neutrons and a atomic mass of 55.845 u

6 0
3 years ago
according to the kinetic molecular theory the pressure exerted by a sample of gas at constats volume doubles when the absolute t
ozzi

Answer: gas molecules will hit the container walls more frequently and with greater force

Explanation:

According to the postulates of  kinetic molecular theory:

1. The pressure exerted by a gas in a container results from collisions between the gas molecules and the container walls.

2. The average kinetic energy of the gas molecules is proportional to the kelvin temperature of the gas.

When the temperature is increased, so the average kinetic energy and the rms speed also increase. This means that the gas molecules will hit the container walls more frequently and with greater force because they are all moving faster. This increase the pressure.

7 0
3 years ago
One calcium atom for every two iodine atoms chemical formula
borishaifa [10]
Is it multiple choice or do you just answer
4 0
2 years ago
How many grams of Cabr2 would be needed to create 450 mL of a 2.00 M solution?
Yanka [14]

Answer:

Mass = 179.9 g

Explanation:

Given data:

Volume of solution = 450 mL

Molarity of solution = 2.00 M

Mass in gram required = ?

Solution:

Volume of solution = 450 mL× 1 L / 1000 mL = 0.45 L

Molarity = number of moles of solute/ Volume of solution in L

2.00 M = number of moles of solute / 0.45 L

Number of moles of solute = 2.00 M × 0.45 L

M = mol/L

number of moles of solute = 0.9 mol

Mass of CaBr₂ in gram:

Mass = number of moles ×  molar  mass

Mass = 0.9 mol ×199.89 g/mol

Mass = 179.9 g

6 0
3 years ago
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