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andreyandreev [35.5K]
3 years ago
8

Help it’s due at a certain time

Chemistry
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

b

Explanation:

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Is making salt water to gurgle for a sore throat a physical or chemical change
Rus_ich [418]

The answer is Physical Change.

4 0
4 years ago
What is the OH in a solution made by adding 0.060 mole of calcium oxide to 500.0ml
Alex73 [517]

Answer:

0.24 mol/L.

Explanation:

  • Ca(OH)₂ dissociates in solution according to the equation:

<em>Ca(OH)₂ → Ca²⁺ + 2OH⁻.</em>

<em></em>

Every 1.0 mol of Ca(OH)₂ dissociates to give 2.0 moles of OH⁻.

∴ The no. of moles of OH⁻ produced from 0.06 mol of Ca(OH)₂ = (2 x 0.06 mol) = 0.12 mol.

<em>∴ [OH⁻] = no. of moles / V of the solution</em> = (0.12 mol)/(0.5 L) = <em>0.24 mol/L.</em>

8 0
4 years ago
Magicians often use ‘flash powder’ in their acts. Flash powder contains 69.0% potassium chlorate (31.9% K, 28.9% Cl, 39.2% O) an
mafiozo [28]

Answer:

\rm K: approximately 22.0\%.

\rm Cl: approximately 19.9\%.

\rm O: approximately 27.0\%.

\rm Al: 31.0\%.

Explanation:

Consider a 100\; \rm g sample. There would be 69.0\% \times 100\; \rm g = 69.0\; \rm g of \rm KClO_{3} and 100.0\; \rm g - 69.0\; \rm g = 31.0\; \rm g of \rm Al.

Out of that 69.0\; \rm g of \rm KClO_{3}:

31.9\% (by mass) would be \rm K: 31.9\% \times 69.0\; \rm g \approx 22.0\; \rm g.

28.9\% (by mass) would be \rm Cl: 28.9\% \times 69.0\; \rm g \approx 19.9\; \rm g.

39.2\% (by mass) would be \rm O: 39.2\% \times 69.0\; \rm g \approx 27.0\; \rm g.

Overall, the composition (by mass) of each element in this mixture would be:

\rm K:

\begin{aligned} & \frac{31.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 31.9\% \times 69.0\% \\ \approx \; & 22.0\%\end{aligned}.

\rm Cl:

\begin{aligned} & \frac{28.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 28.9\% \times 69.0\% \\ \approx \; & 19.9\%\end{aligned}.

\rm O:

\begin{aligned} & \frac{39.2\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 39.2\% \times 69.0\% \\ \approx \; & 27.0\%\end{aligned}.

\rm Al:

\begin{aligned}& \frac{100\; \rm g - 69.0\; \rm g}{100\; \rm g} \\ =\; & 100\% - 69.0\% \\ =\; & 31.0\%\end{aligned}.

7 0
3 years ago
Use ksp=4.87×10−17 to calculate the solubility of iron (ii) hydroxide in pure water in grams per 100.0 ml of solution. g
marysya [2.9K]
The ksp = 4.87 × 10^-17
Therefore; 4.87 ×10^-17 = [Fe2+][OH-]^2 = (X)(2X)^2 = 4X^3
Hence; 
 4x^3 =4.87 × 10^-17 
 x = 2.30 × 10^-6 M
therefore the molarity is 2.3 ×10^-6 M
Thus;
The mass of Fe(OH)2 in 100 ml of water, will be given by:
  = 2.30 × 10^-6 mol/L = 2.3 ×× 10^-5 mole/100 mL
 =  89.86 g/mol × 2.3 × 10^-6 × 0.100 = 2.07 × 10^-5 g
= 2.07 × 10^-5 g 
 = 2.07 × 10^-5 g
5 0
3 years ago
Phosphorus tribromide decomposes to form phosphorus and bromide, like this:
kenny6666 [7]

Answer:

Kp = 9.3x10⁴

Explanation:

The reaction is this:

4PBr₃ (g)  ⇄  P₄ (g) +  6Br₂ (g)

We define Kp from the partial pressures in equilibrium

PBr₃ →  97.4 atm

P₄ →  99.2 atm

Br₂ → 97.2 atm

Kp = (Partial pressure Br₂)⁶ . (Partial pressure P₄) / (Partial pressure PBr₃)⁴

Kp = 97.2⁶ . 99.2 / 97.4⁴

Kp = 929551.4533

929551.4533 → 9.3x10⁴

4 0
3 years ago
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