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tino4ka555 [31]
3 years ago
14

Which of the following statements correctly describes the characteristics of the surface features in Column A and Column B?

Chemistry
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

The surface features in column A are formed by long term processes while the surface features in columns B are formed by short term processes

You might be interested in
Which two substances are covalent compounds? * C6H12O6(s) and KI(s) C6H12O6(s) and HCl(g) KI(s) and NaCl(s) NaCl(s) and HCl(g)
Ray Of Light [21]

Answer: Option (b) is the correct answer.

Explanation:

A covalent compound is defined as the compound in which sharing of electrons take place between the combining atoms. Generally, when two or more non-metals chemically combine together the it will lead to the formation of a covalent compound.

For example, C_{6}H_{12}O_{6} and HCl is also a covalent compound.

And, a compound in which transfer of electrons occur between the combining atoms is known as an ionic compound. Whenever, a metal chemically combines with a non-metal then it will always lead to the formation of an ionic compound.

For example, KI is an ionic compound.

Thus, we can conclude that C_{6}H_{12}O_{6} and HCl are the two substances which are covalent compounds.

7 0
3 years ago
What do oxygen, silicon, and selenium have in common? How might this relate to their organization on the periodic table?
Sonbull [250]

Answer:

They all belong to the p block in the periodic table

Explanation:

Let us examine the electronic configuration of each element;

Oxygen - [He] 2s2 2p4

Silicon - [Ne] 3s2 3p2

Selenium - [Ar] 4s2 3d10 4p4

A common thread that joins all the elements listed above is that they all belong to the p-block in the periodic table. They could be collectively referred to as p-block elements.

8 0
3 years ago
A group of students collects data to determine whether compounds were ionic or covalent. They placed each compound in a small bo
yan [13]

Answer:

the answer is B.  

No, as ionic compounds are only conductive in an aqueous (water) solution

Explanation: i just know

8 0
3 years ago
A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern
Arada [10]

<u>Answer:</u> The volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

<u>Explanation:</u>

  • To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g    (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L

Converting this value into m^3, we use the conversion factor:

1m^3=1000L

So, \Rightarrow (\frac{1m^3}{1000L})\times 154.21L

\Rightarrow 0.1542m^3

  • To calculate the internal energy, we use the equation:

U=\frac{3}{2}nRT

or,

U=\frac{3}{2}\frac{m}{M}RT

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g  (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = 8.314J/K.mol

T = temperature = 60^oC=[60+273]K=333K

Putting values in above equation, we get:

U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is 0.1542m^3 and total internal energy is 162.0 kJ.

6 0
3 years ago
How many joules are required for melting 12.8g of ice at 0 degrees Celsius?
tino4ka555 [31]

Answer:

4,270 Joules

Explanation:

The heat of fusion of water is 334 j/g. So, the equation would be (12.8 g)(334 j/g) which comes to 4,270 joules.

Written out that's just twelve point eight times three hundred and thirty four.

4 0
3 years ago
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